|  |  |  | #include "qr_solve.h"
 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | #ifdef AUTO_BED_LEVELING_GRID
 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | #include <stdlib.h>
 | 
					
						
							|  |  |  | #include <math.h>
 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | //# include "r8lib.h"
 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | int i4_min ( int i1, int i2 ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     I4_MIN returns the smaller of two I4's. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     29 August 2006 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int I1, I2, two integers to be compared. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, int I4_MIN, the smaller of I1 and I2. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int value; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( i1 < i2 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     value = i1; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   else | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     value = i2; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return value; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | double r8_epsilon ( void ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     R8_EPSILON returns the R8 round off unit. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     R8_EPSILON is a number R which is a power of 2 with the property that, | 
					
						
							|  |  |  |     to the precision of the computer's arithmetic, | 
					
						
							|  |  |  |       1 < 1 + R | 
					
						
							|  |  |  |     but | 
					
						
							|  |  |  |       1 = ( 1 + R / 2 ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     01 September 2012 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double R8_EPSILON, the R8 round-off unit. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   const double value = 2.220446049250313E-016; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   return value; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | double r8_max ( double x, double y ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     R8_MAX returns the maximum of two R8's. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     07 May 2006 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double X, Y, the quantities to compare. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double R8_MAX, the maximum of X and Y. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   double value; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( y < x ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     value = x; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   else | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     value = y; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return value; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | double r8_abs ( double x ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     R8_ABS returns the absolute value of an R8. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     07 May 2006 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double X, the quantity whose absolute value is desired. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double R8_ABS, the absolute value of X. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   double value; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( 0.0 <= x ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     value = + x; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   else | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     value = - x; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return value; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | double r8_sign ( double x ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     R8_SIGN returns the sign of an R8. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     08 May 2006 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double X, the number whose sign is desired. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double R8_SIGN, the sign of X. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   double value; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( x < 0.0 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     value = - 1.0; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   else | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     value = + 1.0; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return value; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | double r8mat_amax ( int m, int n, double a[] ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     R8MAT_AMAX returns the maximum absolute value entry of an R8MAT. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     An R8MAT is a doubly dimensioned array of R8 values, stored as a vector | 
					
						
							|  |  |  |     in column-major order. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     07 September 2012 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int M, the number of rows in A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of columns in A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double A[M*N], the M by N matrix. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double R8MAT_AMAX, the maximum absolute value entry of A. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int i; | 
					
						
							|  |  |  |   int j; | 
					
						
							|  |  |  |   double value; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   value = r8_abs ( a[0+0*m] ); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   for ( j = 0; j < n; j++ ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( i = 0; i < m; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       if ( value < r8_abs ( a[i+j*m] ) ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         value = r8_abs ( a[i+j*m] ); | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return value; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | double *r8mat_copy_new ( int m, int n, double a1[] ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     R8MAT_COPY_NEW copies one R8MAT to a "new" R8MAT. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     An R8MAT is a doubly dimensioned array of R8 values, stored as a vector | 
					
						
							|  |  |  |     in column-major order. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     26 July 2008 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int M, N, the number of rows and columns. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double A1[M*N], the matrix to be copied. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double R8MAT_COPY_NEW[M*N], the copy of A1. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   double *a2; | 
					
						
							|  |  |  |   int i; | 
					
						
							|  |  |  |   int j; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   a2 = ( double * ) malloc ( m * n * sizeof ( double ) ); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   for ( j = 0; j < n; j++ ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( i = 0; i < m; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       a2[i+j*m] = a1[i+j*m]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   return a2; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | void daxpy ( int n, double da, double dx[], int incx, double dy[], int incy ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DAXPY computes constant times a vector plus a vector. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This routine uses unrolled loops for increments equal to one. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license.  | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     30 March 2007 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch, Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, 1979. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Charles Lawson, Richard Hanson, David Kincaid, Fred Krogh, | 
					
						
							|  |  |  |     Basic Linear Algebra Subprograms for Fortran Usage, | 
					
						
							|  |  |  |     Algorithm 539,  | 
					
						
							|  |  |  |     ACM Transactions on Mathematical Software,  | 
					
						
							|  |  |  |     Volume 5, Number 3, September 1979, pages 308-323. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of elements in DX and DY. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double DA, the multiplier of DX. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double DX[*], the first vector. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCX, the increment between successive entries of DX. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, double DY[*], the second vector. | 
					
						
							|  |  |  |     On output, DY[*] has been replaced by DY[*] + DA * DX[*]. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCY, the increment between successive entries of DY. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int i; | 
					
						
							|  |  |  |   int ix; | 
					
						
							|  |  |  |   int iy; | 
					
						
							|  |  |  |   int m; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( n <= 0 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     return; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( da == 0.0 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     return; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Code for unequal increments or equal increments | 
					
						
							|  |  |  |   not equal to 1. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   if ( incx != 1 || incy != 1 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     if ( 0 <= incx ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       ix = 0; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     else | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       ix = ( - n + 1 ) * incx; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     if ( 0 <= incy ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       iy = 0; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     else | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       iy = ( - n + 1 ) * incy; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( i = 0; i < n; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       dy[iy] = dy[iy] + da * dx[ix]; | 
					
						
							|  |  |  |       ix = ix + incx; | 
					
						
							|  |  |  |       iy = iy + incy; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Code for both increments equal to 1. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   else | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     m = n % 4; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( i = 0; i < m; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       dy[i] = dy[i] + da * dx[i]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( i = m; i < n; i = i + 4 ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       dy[i  ] = dy[i  ] + da * dx[i  ]; | 
					
						
							|  |  |  |       dy[i+1] = dy[i+1] + da * dx[i+1]; | 
					
						
							|  |  |  |       dy[i+2] = dy[i+2] + da * dx[i+2]; | 
					
						
							|  |  |  |       dy[i+3] = dy[i+3] + da * dx[i+3]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | double ddot ( int n, double dx[], int incx, double dy[], int incy ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DDOT forms the dot product of two vectors. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This routine uses unrolled loops for increments equal to one. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license.  | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     30 March 2007 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch, Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, 1979. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Charles Lawson, Richard Hanson, David Kincaid, Fred Krogh, | 
					
						
							|  |  |  |     Basic Linear Algebra Subprograms for Fortran Usage, | 
					
						
							|  |  |  |     Algorithm 539,  | 
					
						
							|  |  |  |     ACM Transactions on Mathematical Software,  | 
					
						
							|  |  |  |     Volume 5, Number 3, September 1979, pages 308-323. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of entries in the vectors. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double DX[*], the first vector. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCX, the increment between successive entries in DX. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double DY[*], the second vector. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCY, the increment between successive entries in DY. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double DDOT, the sum of the product of the corresponding | 
					
						
							|  |  |  |     entries of DX and DY. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   double dtemp; | 
					
						
							|  |  |  |   int i; | 
					
						
							|  |  |  |   int ix; | 
					
						
							|  |  |  |   int iy; | 
					
						
							|  |  |  |   int m; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   dtemp = 0.0; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( n <= 0 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     return dtemp; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Code for unequal increments or equal increments | 
					
						
							|  |  |  |   not equal to 1. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   if ( incx != 1 || incy != 1 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     if ( 0 <= incx ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       ix = 0; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     else | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       ix = ( - n + 1 ) * incx; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     if ( 0 <= incy ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       iy = 0; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     else | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       iy = ( - n + 1 ) * incy; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( i = 0; i < n; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       dtemp = dtemp + dx[ix] * dy[iy]; | 
					
						
							|  |  |  |       ix = ix + incx; | 
					
						
							|  |  |  |       iy = iy + incy; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Code for both increments equal to 1. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   else | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     m = n % 5; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( i = 0; i < m; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       dtemp = dtemp + dx[i] * dy[i]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( i = m; i < n; i = i + 5 ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       dtemp = dtemp + dx[i  ] * dy[i  ]  | 
					
						
							|  |  |  |                     + dx[i+1] * dy[i+1]  | 
					
						
							|  |  |  |                     + dx[i+2] * dy[i+2]  | 
					
						
							|  |  |  |                     + dx[i+3] * dy[i+3]  | 
					
						
							|  |  |  |                     + dx[i+4] * dy[i+4]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return dtemp; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | double dnrm2 ( int n, double x[], int incx ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DNRM2 returns the euclidean norm of a vector. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |      DNRM2 ( X ) = sqrt ( X' * X ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license.  | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     30 March 2007 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch, Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, 1979. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Charles Lawson, Richard Hanson, David Kincaid, Fred Krogh, | 
					
						
							|  |  |  |     Basic Linear Algebra Subprograms for Fortran Usage, | 
					
						
							|  |  |  |     Algorithm 539, | 
					
						
							|  |  |  |     ACM Transactions on Mathematical Software, | 
					
						
							|  |  |  |     Volume 5, Number 3, September 1979, pages 308-323. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of entries in the vector. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double X[*], the vector whose norm is to be computed. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCX, the increment between successive entries of X. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double DNRM2, the Euclidean norm of X. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   double absxi; | 
					
						
							|  |  |  |   int i; | 
					
						
							|  |  |  |   int ix; | 
					
						
							|  |  |  |   double norm; | 
					
						
							|  |  |  |   double scale; | 
					
						
							|  |  |  |   double ssq; | 
					
						
							|  |  |  |   double value; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( n < 1 || incx < 1 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     norm = 0.0; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   else if ( n == 1 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     norm = r8_abs ( x[0] ); | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   else | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     scale = 0.0; | 
					
						
							|  |  |  |     ssq = 1.0; | 
					
						
							|  |  |  |     ix = 0; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( i = 0; i < n; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       if ( x[ix] != 0.0 ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         absxi = r8_abs ( x[ix] ); | 
					
						
							|  |  |  |         if ( scale < absxi ) | 
					
						
							|  |  |  |         { | 
					
						
							|  |  |  |           ssq = 1.0 + ssq * ( scale / absxi ) * ( scale / absxi ); | 
					
						
							|  |  |  |           scale = absxi; | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  |         else | 
					
						
							|  |  |  |         { | 
					
						
							|  |  |  |           ssq = ssq + ( absxi / scale ) * ( absxi / scale ); | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |       ix = ix + incx; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     norm  = scale * sqrt ( ssq ); | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   return norm; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | void dqrank ( double a[], int lda, int m, int n, double tol, int *kr,  | 
					
						
							|  |  |  |   int jpvt[], double qraux[] ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRANK computes the QR factorization of a rectangular matrix. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This routine is used in conjunction with DQRLSS to solve | 
					
						
							|  |  |  |     overdetermined, underdetermined and singular linear systems | 
					
						
							|  |  |  |     in a least squares sense. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRANK uses the LINPACK subroutine DQRDC to compute the QR | 
					
						
							|  |  |  |     factorization, with column pivoting, of an M by N matrix A. | 
					
						
							|  |  |  |     The numerical rank is determined using the tolerance TOL. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Note that on output, ABS ( A(1,1) ) / ABS ( A(KR,KR) ) is an estimate | 
					
						
							|  |  |  |     of the condition number of the matrix of independent columns, | 
					
						
							|  |  |  |     and of R.  This estimate will be <= 1/TOL. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license.  | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     21 April 2012 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch, Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, 1979, | 
					
						
							|  |  |  |     ISBN13: 978-0-898711-72-1, | 
					
						
							|  |  |  |     LC: QA214.L56. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, double A[LDA*N].  On input, the matrix whose | 
					
						
							|  |  |  |     decomposition is to be computed.  On output, the information from DQRDC. | 
					
						
							|  |  |  |     The triangular matrix R of the QR factorization is contained in the | 
					
						
							|  |  |  |     upper triangle and information needed to recover the orthogonal | 
					
						
							|  |  |  |     matrix Q is stored below the diagonal in A and in the vector QRAUX. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int LDA, the leading dimension of A, which must | 
					
						
							|  |  |  |     be at least M. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int M, the number of rows of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of columns of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double TOL, a relative tolerance used to determine the | 
					
						
							|  |  |  |     numerical rank.  The problem should be scaled so that all the elements | 
					
						
							|  |  |  |     of A have roughly the same absolute accuracy, EPS.  Then a reasonable | 
					
						
							|  |  |  |     value for TOL is roughly EPS divided by the magnitude of the largest | 
					
						
							|  |  |  |     element. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, int *KR, the numerical rank. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, int JPVT[N], the pivot information from DQRDC. | 
					
						
							|  |  |  |     Columns JPVT(1), ..., JPVT(KR) of the original matrix are linearly | 
					
						
							|  |  |  |     independent to within the tolerance TOL and the remaining columns | 
					
						
							|  |  |  |     are linearly dependent. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double QRAUX[N], will contain extra information defining | 
					
						
							|  |  |  |     the QR factorization. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int i; | 
					
						
							|  |  |  |   int j; | 
					
						
							|  |  |  |   int job; | 
					
						
							|  |  |  |   int k; | 
					
						
							|  |  |  |   double *work; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   for ( i = 0; i < n; i++ ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     jpvt[i] = 0; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   work = ( double * ) malloc ( n * sizeof ( double ) ); | 
					
						
							|  |  |  |   job = 1; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   dqrdc ( a, lda, m, n, qraux, jpvt, work, job ); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   *kr = 0; | 
					
						
							|  |  |  |   k = i4_min ( m, n ); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   for ( j = 0; j < k; j++ ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     if ( r8_abs ( a[j+j*lda] ) <= tol * r8_abs ( a[0+0*lda] ) ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       return; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     *kr = j + 1; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   free ( work ); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   return; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | void dqrdc ( double a[], int lda, int n, int p, double qraux[], int jpvt[],  | 
					
						
							|  |  |  |   double work[], int job ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRDC computes the QR factorization of a real rectangular matrix. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRDC uses Householder transformations. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Column pivoting based on the 2-norms of the reduced columns may be | 
					
						
							|  |  |  |     performed at the user's option. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license.  | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     07 June 2005 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch and Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, (Society for Industrial and Applied Mathematics), | 
					
						
							|  |  |  |     3600 University City Science Center, | 
					
						
							|  |  |  |     Philadelphia, PA, 19104-2688. | 
					
						
							|  |  |  |     ISBN 0-89871-172-X | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, double A(LDA,P).  On input, the N by P matrix | 
					
						
							|  |  |  |     whose decomposition is to be computed.  On output, A contains in | 
					
						
							|  |  |  |     its upper triangle the upper triangular matrix R of the QR | 
					
						
							|  |  |  |     factorization.  Below its diagonal A contains information from | 
					
						
							|  |  |  |     which the orthogonal part of the decomposition can be recovered. | 
					
						
							|  |  |  |     Note that if pivoting has been requested, the decomposition is not that | 
					
						
							|  |  |  |     of the original matrix A but that of A with its columns permuted | 
					
						
							|  |  |  |     as described by JPVT. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int LDA, the leading dimension of the array A.  LDA must | 
					
						
							|  |  |  |     be at least N. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of rows of the matrix A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int P, the number of columns of the matrix A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double QRAUX[P], contains further information required | 
					
						
							|  |  |  |     to recover the orthogonal part of the decomposition. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, integer JPVT[P].  On input, JPVT contains integers that | 
					
						
							|  |  |  |     control the selection of the pivot columns.  The K-th column A(*,K) of A | 
					
						
							|  |  |  |     is placed in one of three classes according to the value of JPVT(K). | 
					
						
							|  |  |  |       > 0, then A(K) is an initial column. | 
					
						
							|  |  |  |       = 0, then A(K) is a free column. | 
					
						
							|  |  |  |       < 0, then A(K) is a final column. | 
					
						
							|  |  |  |     Before the decomposition is computed, initial columns are moved to | 
					
						
							|  |  |  |     the beginning of the array A and final columns to the end.  Both | 
					
						
							|  |  |  |     initial and final columns are frozen in place during the computation | 
					
						
							|  |  |  |     and only free columns are moved.  At the K-th stage of the | 
					
						
							|  |  |  |     reduction, if A(*,K) is occupied by a free column it is interchanged | 
					
						
							|  |  |  |     with the free column of largest reduced norm.  JPVT is not referenced | 
					
						
							|  |  |  |     if JOB == 0.  On output, JPVT(K) contains the index of the column of the | 
					
						
							|  |  |  |     original matrix that has been interchanged into the K-th column, if | 
					
						
							|  |  |  |     pivoting was requested. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Workspace, double WORK[P].  WORK is not referenced if JOB == 0. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int JOB, initiates column pivoting. | 
					
						
							|  |  |  |     0, no pivoting is done. | 
					
						
							|  |  |  |     nonzero, pivoting is done. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int j; | 
					
						
							|  |  |  |   int jp; | 
					
						
							|  |  |  |   int l; | 
					
						
							|  |  |  |   int lup; | 
					
						
							|  |  |  |   int maxj; | 
					
						
							|  |  |  |   double maxnrm; | 
					
						
							|  |  |  |   double nrmxl; | 
					
						
							|  |  |  |   int pl; | 
					
						
							|  |  |  |   int pu; | 
					
						
							|  |  |  |   int swapj; | 
					
						
							|  |  |  |   double t; | 
					
						
							|  |  |  |   double tt; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   pl = 1; | 
					
						
							|  |  |  |   pu = 0; | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   If pivoting is requested, rearrange the columns. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   if ( job != 0 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( j = 1; j <= p; j++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       swapj = ( 0 < jpvt[j-1] ); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       if ( jpvt[j-1] < 0 ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         jpvt[j-1] = -j; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |       else | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         jpvt[j-1] = j; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       if ( swapj ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         if ( j != pl ) | 
					
						
							|  |  |  |         { | 
					
						
							|  |  |  |           dswap ( n, a+0+(pl-1)*lda, 1, a+0+(j-1), 1 ); | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  |         jpvt[j-1] = jpvt[pl-1]; | 
					
						
							|  |  |  |         jpvt[pl-1] = j; | 
					
						
							|  |  |  |         pl = pl + 1; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     pu = p; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( j = p; 1 <= j; j-- ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       if ( jpvt[j-1] < 0 ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         jpvt[j-1] = -jpvt[j-1]; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |         if ( j != pu ) | 
					
						
							|  |  |  |         { | 
					
						
							|  |  |  |           dswap ( n, a+0+(pu-1)*lda, 1, a+0+(j-1)*lda, 1 ); | 
					
						
							|  |  |  |           jp = jpvt[pu-1]; | 
					
						
							|  |  |  |           jpvt[pu-1] = jpvt[j-1]; | 
					
						
							|  |  |  |           jpvt[j-1] = jp; | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  |         pu = pu - 1; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Compute the norms of the free columns. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   for ( j = pl; j <= pu; j++ ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     qraux[j-1] = dnrm2 ( n, a+0+(j-1)*lda, 1 ); | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   for ( j = pl; j <= pu; j++ ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     work[j-1] = qraux[j-1]; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Perform the Householder reduction of A. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   lup = i4_min ( n, p ); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   for ( l = 1; l <= lup; l++ ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Bring the column of largest norm into the pivot position. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |     if ( pl <= l && l < pu ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       maxnrm = 0.0; | 
					
						
							|  |  |  |       maxj = l; | 
					
						
							|  |  |  |       for ( j = l; j <= pu; j++ ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         if ( maxnrm < qraux[j-1] ) | 
					
						
							|  |  |  |         { | 
					
						
							|  |  |  |           maxnrm = qraux[j-1]; | 
					
						
							|  |  |  |           maxj = j; | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       if ( maxj != l ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         dswap ( n, a+0+(l-1)*lda, 1, a+0+(maxj-1)*lda, 1 ); | 
					
						
							|  |  |  |         qraux[maxj-1] = qraux[l-1]; | 
					
						
							|  |  |  |         work[maxj-1] = work[l-1]; | 
					
						
							|  |  |  |         jp = jpvt[maxj-1]; | 
					
						
							|  |  |  |         jpvt[maxj-1] = jpvt[l-1]; | 
					
						
							|  |  |  |         jpvt[l-1] = jp; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Compute the Householder transformation for column L. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |     qraux[l-1] = 0.0; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     if ( l != n ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       nrmxl = dnrm2 ( n-l+1, a+l-1+(l-1)*lda, 1 ); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       if ( nrmxl != 0.0 ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         if ( a[l-1+(l-1)*lda] != 0.0 ) | 
					
						
							|  |  |  |         { | 
					
						
							|  |  |  |           nrmxl = nrmxl * r8_sign ( a[l-1+(l-1)*lda] ); | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |         dscal ( n-l+1, 1.0 / nrmxl, a+l-1+(l-1)*lda, 1 ); | 
					
						
							|  |  |  |         a[l-1+(l-1)*lda] = 1.0 + a[l-1+(l-1)*lda]; | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Apply the transformation to the remaining columns, updating the norms. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |         for ( j = l + 1; j <= p; j++ ) | 
					
						
							|  |  |  |         { | 
					
						
							|  |  |  |           t = -ddot ( n-l+1, a+l-1+(l-1)*lda, 1, a+l-1+(j-1)*lda, 1 )  | 
					
						
							|  |  |  |             / a[l-1+(l-1)*lda]; | 
					
						
							|  |  |  |           daxpy ( n-l+1, t, a+l-1+(l-1)*lda, 1, a+l-1+(j-1)*lda, 1 ); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |           if ( pl <= j && j <= pu ) | 
					
						
							|  |  |  |           { | 
					
						
							|  |  |  |             if ( qraux[j-1] != 0.0 ) | 
					
						
							|  |  |  |             { | 
					
						
							|  |  |  |               tt = 1.0 - pow ( r8_abs ( a[l-1+(j-1)*lda] ) / qraux[j-1], 2 ); | 
					
						
							|  |  |  |               tt = r8_max ( tt, 0.0 ); | 
					
						
							|  |  |  |               t = tt; | 
					
						
							|  |  |  |               tt = 1.0 + 0.05 * tt * pow ( qraux[j-1] / work[j-1], 2 ); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |               if ( tt != 1.0 ) | 
					
						
							|  |  |  |               { | 
					
						
							|  |  |  |                 qraux[j-1] = qraux[j-1] * sqrt ( t ); | 
					
						
							|  |  |  |               } | 
					
						
							|  |  |  |               else | 
					
						
							|  |  |  |               { | 
					
						
							|  |  |  |                 qraux[j-1] = dnrm2 ( n-l, a+l+(j-1)*lda, 1 ); | 
					
						
							|  |  |  |                 work[j-1] = qraux[j-1]; | 
					
						
							|  |  |  |               } | 
					
						
							|  |  |  |             } | 
					
						
							|  |  |  |           } | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Save the transformation. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |         qraux[l-1] = a[l-1+(l-1)*lda]; | 
					
						
							|  |  |  |         a[l-1+(l-1)*lda] = -nrmxl; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | int dqrls ( double a[], int lda, int m, int n, double tol, int *kr, double b[],  | 
					
						
							|  |  |  |   double x[], double rsd[], int jpvt[], double qraux[], int itask ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRLS factors and solves a linear system in the least squares sense. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     The linear system may be overdetermined, underdetermined or singular. | 
					
						
							|  |  |  |     The solution is obtained using a QR factorization of the | 
					
						
							|  |  |  |     coefficient matrix. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRLS can be efficiently used to solve several least squares | 
					
						
							|  |  |  |     problems with the same matrix A.  The first system is solved | 
					
						
							|  |  |  |     with ITASK = 1.  The subsequent systems are solved with | 
					
						
							|  |  |  |     ITASK = 2, to avoid the recomputation of the matrix factors. | 
					
						
							|  |  |  |     The parameters KR, JPVT, and QRAUX must not be modified | 
					
						
							|  |  |  |     between calls to DQRLS. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRLS is used to solve in a least squares sense | 
					
						
							|  |  |  |     overdetermined, underdetermined and singular linear systems. | 
					
						
							|  |  |  |     The system is A*X approximates B where A is M by N. | 
					
						
							|  |  |  |     B is a given M-vector, and X is the N-vector to be computed. | 
					
						
							|  |  |  |     A solution X is found which minimimzes the sum of squares (2-norm) | 
					
						
							|  |  |  |     of the residual,  A*X - B. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     The numerical rank of A is determined using the tolerance TOL. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRLS uses the LINPACK subroutine DQRDC to compute the QR | 
					
						
							|  |  |  |     factorization, with column pivoting, of an M by N matrix A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license.  | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     10 September 2012 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     David Kahaner, Cleve Moler, Steven Nash, | 
					
						
							|  |  |  |     Numerical Methods and Software, | 
					
						
							|  |  |  |     Prentice Hall, 1989, | 
					
						
							|  |  |  |     ISBN: 0-13-627258-4, | 
					
						
							|  |  |  |     LC: TA345.K34. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, double A[LDA*N], an M by N matrix. | 
					
						
							|  |  |  |     On input, the matrix whose decomposition is to be computed. | 
					
						
							|  |  |  |     In a least squares data fitting problem, A(I,J) is the | 
					
						
							|  |  |  |     value of the J-th basis (model) function at the I-th data point. | 
					
						
							|  |  |  |     On output, A contains the output from DQRDC.  The triangular matrix R | 
					
						
							|  |  |  |     of the QR factorization is contained in the upper triangle and | 
					
						
							|  |  |  |     information needed to recover the orthogonal matrix Q is stored | 
					
						
							|  |  |  |     below the diagonal in A and in the vector QRAUX. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int LDA, the leading dimension of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int M, the number of rows of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of columns of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double TOL, a relative tolerance used to determine the | 
					
						
							|  |  |  |     numerical rank.  The problem should be scaled so that all the elements | 
					
						
							|  |  |  |     of A have roughly the same absolute accuracy EPS.  Then a reasonable | 
					
						
							|  |  |  |     value for TOL is roughly EPS divided by the magnitude of the largest | 
					
						
							|  |  |  |     element. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, int *KR, the numerical rank. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double B[M], the right hand side of the linear system. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double X[N], a least squares solution to the linear | 
					
						
							|  |  |  |     system. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double RSD[M], the residual, B - A*X.  RSD may | 
					
						
							|  |  |  |     overwrite B. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Workspace, int JPVT[N], required if ITASK = 1. | 
					
						
							|  |  |  |     Columns JPVT(1), ..., JPVT(KR) of the original matrix are linearly | 
					
						
							|  |  |  |     independent to within the tolerance TOL and the remaining columns | 
					
						
							|  |  |  |     are linearly dependent.  ABS ( A(1,1) ) / ABS ( A(KR,KR) ) is an estimate | 
					
						
							|  |  |  |     of the condition number of the matrix of independent columns, | 
					
						
							|  |  |  |     and of R.  This estimate will be <= 1/TOL. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Workspace, double QRAUX[N], required if ITASK = 1. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int ITASK. | 
					
						
							|  |  |  |     1, DQRLS factors the matrix A and solves the least squares problem. | 
					
						
							|  |  |  |     2, DQRLS assumes that the matrix A was factored with an earlier | 
					
						
							|  |  |  |        call to DQRLS, and only solves the least squares problem. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, int DQRLS, error code. | 
					
						
							|  |  |  |     0:  no error | 
					
						
							|  |  |  |     -1: LDA < M   (fatal error) | 
					
						
							|  |  |  |     -2: N < 1     (fatal error) | 
					
						
							|  |  |  |     -3: ITASK < 1 (fatal error) | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int ind; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( lda < m ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     /*fprintf ( stderr, "\n" );
 | 
					
						
							|  |  |  |     fprintf ( stderr, "DQRLS - Fatal error!\n" ); | 
					
						
							|  |  |  |     fprintf ( stderr, "  LDA < M.\n" );*/ | 
					
						
							|  |  |  |     ind = -1; | 
					
						
							|  |  |  |     return ind; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( n <= 0 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     /*fprintf ( stderr, "\n" );
 | 
					
						
							|  |  |  |     fprintf ( stderr, "DQRLS - Fatal error!\n" ); | 
					
						
							|  |  |  |     fprintf ( stderr, "  N <= 0.\n" );*/ | 
					
						
							|  |  |  |     ind = -2; | 
					
						
							|  |  |  |     return ind; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( itask < 1 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     /*fprintf ( stderr, "\n" );
 | 
					
						
							|  |  |  |     fprintf ( stderr, "DQRLS - Fatal error!\n" ); | 
					
						
							|  |  |  |     fprintf ( stderr, "  ITASK < 1.\n" );*/ | 
					
						
							|  |  |  |     ind = -3; | 
					
						
							|  |  |  |     return ind; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   ind = 0; | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Factor the matrix. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   if ( itask == 1 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     dqrank ( a, lda, m, n, tol, kr, jpvt, qraux ); | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Solve the least-squares problem. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   dqrlss ( a, lda, m, n, *kr, b, x, rsd, jpvt, qraux ); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   return ind; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | void dqrlss ( double a[], int lda, int m, int n, int kr, double b[], double x[],  | 
					
						
							|  |  |  |   double rsd[], int jpvt[], double qraux[] ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRLSS solves a linear system in a least squares sense. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRLSS must be preceded by a call to DQRANK. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     The system is to be solved is | 
					
						
							|  |  |  |       A * X = B | 
					
						
							|  |  |  |     where | 
					
						
							|  |  |  |       A is an M by N matrix with rank KR, as determined by DQRANK, | 
					
						
							|  |  |  |       B is a given M-vector, | 
					
						
							|  |  |  |       X is the N-vector to be computed. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     A solution X, with at most KR nonzero components, is found which | 
					
						
							|  |  |  |     minimizes the 2-norm of the residual (A*X-B). | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Once the matrix A has been formed, DQRANK should be | 
					
						
							|  |  |  |     called once to decompose it.  Then, for each right hand | 
					
						
							|  |  |  |     side B, DQRLSS should be called once to obtain the | 
					
						
							|  |  |  |     solution and residual. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license.  | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     10 September 2012 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double A[LDA*N], the QR factorization information | 
					
						
							|  |  |  |     from DQRANK.  The triangular matrix R of the QR factorization is | 
					
						
							|  |  |  |     contained in the upper triangle and information needed to recover | 
					
						
							|  |  |  |     the orthogonal matrix Q is stored below the diagonal in A and in | 
					
						
							|  |  |  |     the vector QRAUX. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int LDA, the leading dimension of A, which must | 
					
						
							|  |  |  |     be at least M. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int M, the number of rows of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of columns of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int KR, the rank of the matrix, as estimated by DQRANK. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double B[M], the right hand side of the linear system. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double X[N], a least squares solution to the | 
					
						
							|  |  |  |     linear system. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double RSD[M], the residual, B - A*X.  RSD may | 
					
						
							|  |  |  |     overwrite B. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int JPVT[N], the pivot information from DQRANK. | 
					
						
							|  |  |  |     Columns JPVT[0], ..., JPVT[KR-1] of the original matrix are linearly | 
					
						
							|  |  |  |     independent to within the tolerance TOL and the remaining columns | 
					
						
							|  |  |  |     are linearly dependent. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double QRAUX[N], auxiliary information from DQRANK | 
					
						
							|  |  |  |     defining the QR factorization. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int i; | 
					
						
							|  |  |  |   int info; | 
					
						
							|  |  |  |   int j; | 
					
						
							|  |  |  |   int job; | 
					
						
							|  |  |  |   int k; | 
					
						
							|  |  |  |   double t; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( kr != 0 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     job = 110; | 
					
						
							|  |  |  |     info = dqrsl ( a, lda, m, kr, qraux, b, rsd, rsd, x, rsd, rsd, job ); | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   for ( i = 0; i < n; i++ ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     jpvt[i] = - jpvt[i]; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   for ( i = kr; i < n; i++ ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     x[i] = 0.0; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   for ( j = 1; j <= n; j++ ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     if ( jpvt[j-1] <= 0 ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       k = - jpvt[j-1]; | 
					
						
							|  |  |  |       jpvt[j-1] = k; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       while ( k != j ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         t = x[j-1]; | 
					
						
							|  |  |  |         x[j-1] = x[k-1]; | 
					
						
							|  |  |  |         x[k-1] = t; | 
					
						
							|  |  |  |         jpvt[k-1] = -jpvt[k-1]; | 
					
						
							|  |  |  |         k = jpvt[k-1]; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | int dqrsl ( double a[], int lda, int n, int k, double qraux[], double y[],  | 
					
						
							|  |  |  |   double qy[], double qty[], double b[], double rsd[], double ab[], int job ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRSL computes transformations, projections, and least squares solutions. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRSL requires the output of DQRDC. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     For K <= min(N,P), let AK be the matrix | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       AK = ( A(JPVT[0]), A(JPVT(2)), ..., A(JPVT(K)) ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     formed from columns JPVT[0], ..., JPVT(K) of the original | 
					
						
							|  |  |  |     N by P matrix A that was input to DQRDC.  If no pivoting was | 
					
						
							|  |  |  |     done, AK consists of the first K columns of A in their | 
					
						
							|  |  |  |     original order.  DQRDC produces a factored orthogonal matrix Q | 
					
						
							|  |  |  |     and an upper triangular matrix R such that | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       AK = Q * (R) | 
					
						
							|  |  |  |                (0) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This information is contained in coded form in the arrays | 
					
						
							|  |  |  |     A and QRAUX. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     The parameters QY, QTY, B, RSD, and AB are not referenced | 
					
						
							|  |  |  |     if their computation is not requested and in this case | 
					
						
							|  |  |  |     can be replaced by dummy variables in the calling program. | 
					
						
							|  |  |  |     To save storage, the user may in some cases use the same | 
					
						
							|  |  |  |     array for different parameters in the calling sequence.  A | 
					
						
							|  |  |  |     frequently occurring example is when one wishes to compute | 
					
						
							|  |  |  |     any of B, RSD, or AB and does not need Y or QTY.  In this | 
					
						
							|  |  |  |     case one may identify Y, QTY, and one of B, RSD, or AB, while | 
					
						
							|  |  |  |     providing separate arrays for anything else that is to be | 
					
						
							|  |  |  |     computed. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Thus the calling sequence | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       dqrsl ( a, lda, n, k, qraux, y, dum, y, b, y, dum, 110, info ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     will result in the computation of B and RSD, with RSD | 
					
						
							|  |  |  |     overwriting Y.  More generally, each item in the following | 
					
						
							|  |  |  |     list contains groups of permissible identifications for | 
					
						
							|  |  |  |     a single calling sequence. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       1. (Y,QTY,B) (RSD) (AB) (QY) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       2. (Y,QTY,RSD) (B) (AB) (QY) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       3. (Y,QTY,AB) (B) (RSD) (QY) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       4. (Y,QY) (QTY,B) (RSD) (AB) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       5. (Y,QY) (QTY,RSD) (B) (AB) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       6. (Y,QY) (QTY,AB) (B) (RSD) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     In any group the value returned in the array allocated to | 
					
						
							|  |  |  |     the group corresponds to the last member of the group. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license.  | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     07 June 2005 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch and Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, (Society for Industrial and Applied Mathematics), | 
					
						
							|  |  |  |     3600 University City Science Center, | 
					
						
							|  |  |  |     Philadelphia, PA, 19104-2688. | 
					
						
							|  |  |  |     ISBN 0-89871-172-X | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double A[LDA*P], contains the output of DQRDC. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int LDA, the leading dimension of the array A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of rows of the matrix AK.  It must | 
					
						
							|  |  |  |     have the same value as N in DQRDC. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int K, the number of columns of the matrix AK.  K | 
					
						
							|  |  |  |     must not be greater than min(N,P), where P is the same as in the | 
					
						
							|  |  |  |     calling sequence to DQRDC. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double QRAUX[P], the auxiliary output from DQRDC. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double Y[N], a vector to be manipulated by DQRSL. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double QY[N], contains Q * Y, if requested. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double QTY[N], contains Q' * Y, if requested. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double B[K], the solution of the least squares problem | 
					
						
							|  |  |  |       minimize norm2 ( Y - AK * B), | 
					
						
							|  |  |  |     if its computation has been requested.  Note that if pivoting was | 
					
						
							|  |  |  |     requested in DQRDC, the J-th component of B will be associated with | 
					
						
							|  |  |  |     column JPVT(J) of the original matrix A that was input into DQRDC. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double RSD[N], the least squares residual Y - AK * B, | 
					
						
							|  |  |  |     if its computation has been requested.  RSD is also the orthogonal | 
					
						
							|  |  |  |     projection of Y onto the orthogonal complement of the column space | 
					
						
							|  |  |  |     of AK. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double AB[N], the least squares approximation Ak * B, | 
					
						
							|  |  |  |     if its computation has been requested.  AB is also the orthogonal | 
					
						
							|  |  |  |     projection of Y onto the column space of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, integer JOB, specifies what is to be computed.  JOB has | 
					
						
							|  |  |  |     the decimal expansion ABCDE, with the following meaning: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       if A != 0, compute QY. | 
					
						
							|  |  |  |       if B != 0, compute QTY. | 
					
						
							|  |  |  |       if C != 0, compute QTY and B. | 
					
						
							|  |  |  |       if D != 0, compute QTY and RSD. | 
					
						
							|  |  |  |       if E != 0, compute QTY and AB. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Note that a request to compute B, RSD, or AB automatically triggers | 
					
						
							|  |  |  |     the computation of QTY, for which an array must be provided in the | 
					
						
							|  |  |  |     calling sequence. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, int DQRSL, is zero unless the computation of B has | 
					
						
							|  |  |  |     been requested and R is exactly singular.  In this case, INFO is the | 
					
						
							|  |  |  |     index of the first zero diagonal element of R, and B is left unaltered. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int cab; | 
					
						
							|  |  |  |   int cb; | 
					
						
							|  |  |  |   int cqty; | 
					
						
							|  |  |  |   int cqy; | 
					
						
							|  |  |  |   int cr; | 
					
						
							|  |  |  |   int i; | 
					
						
							|  |  |  |   int info; | 
					
						
							|  |  |  |   int j; | 
					
						
							|  |  |  |   int jj; | 
					
						
							|  |  |  |   int ju; | 
					
						
							|  |  |  |   double t; | 
					
						
							|  |  |  |   double temp; | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Set INFO flag. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   info = 0; | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Determine what is to be computed. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   cqy =  (   job / 10000          != 0 ); | 
					
						
							|  |  |  |   cqty = ( ( job %  10000 )       != 0 ); | 
					
						
							|  |  |  |   cb =   ( ( job %   1000 ) / 100 != 0 ); | 
					
						
							|  |  |  |   cr =   ( ( job %    100 ) /  10 != 0 ); | 
					
						
							|  |  |  |   cab =  ( ( job %     10 )       != 0 ); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   ju = i4_min ( k, n-1 ); | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Special action when N = 1. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   if ( ju == 0 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     if ( cqy ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       qy[0] = y[0]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     if ( cqty ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       qty[0] = y[0]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     if ( cab ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       ab[0] = y[0]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     if ( cb ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       if ( a[0+0*lda] == 0.0 ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         info = 1; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |       else | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         b[0] = y[0] / a[0+0*lda]; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     if ( cr ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       rsd[0] = 0.0; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     return info; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Set up to compute QY or QTY. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   if ( cqy ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( i = 1; i <= n; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       qy[i-1] = y[i-1]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( cqty ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( i = 1; i <= n; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       qty[i-1] = y[i-1]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Compute QY. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   if ( cqy ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( jj = 1; jj <= ju; jj++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       j = ju - jj + 1; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       if ( qraux[j-1] != 0.0 ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         temp = a[j-1+(j-1)*lda]; | 
					
						
							|  |  |  |         a[j-1+(j-1)*lda] = qraux[j-1]; | 
					
						
							|  |  |  |         t = -ddot ( n-j+1, a+j-1+(j-1)*lda, 1, qy+j-1, 1 ) / a[j-1+(j-1)*lda]; | 
					
						
							|  |  |  |         daxpy ( n-j+1, t, a+j-1+(j-1)*lda, 1, qy+j-1, 1 ); | 
					
						
							|  |  |  |         a[j-1+(j-1)*lda] = temp; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Compute Q'*Y. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   if ( cqty ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( j = 1; j <= ju; j++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       if ( qraux[j-1] != 0.0 ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         temp = a[j-1+(j-1)*lda]; | 
					
						
							|  |  |  |         a[j-1+(j-1)*lda] = qraux[j-1]; | 
					
						
							|  |  |  |         t = -ddot ( n-j+1, a+j-1+(j-1)*lda, 1, qty+j-1, 1 ) / a[j-1+(j-1)*lda]; | 
					
						
							|  |  |  |         daxpy ( n-j+1, t, a+j-1+(j-1)*lda, 1, qty+j-1, 1 ); | 
					
						
							|  |  |  |         a[j-1+(j-1)*lda] = temp; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Set up to compute B, RSD, or AB. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   if ( cb ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( i = 1; i <= k; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       b[i-1] = qty[i-1]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( cab ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( i = 1; i <= k; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       ab[i-1] = qty[i-1]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( cr && k < n ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( i = k+1; i <= n; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       rsd[i-1] = qty[i-1]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( cab && k+1 <= n ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( i = k+1; i <= n; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       ab[i-1] = 0.0; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( cr ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( i = 1; i <= k; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       rsd[i-1] = 0.0; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Compute B. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   if ( cb ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( jj = 1; jj <= k; jj++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       j = k - jj + 1; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       if ( a[j-1+(j-1)*lda] == 0.0 ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         info = j; | 
					
						
							|  |  |  |         break; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       b[j-1] = b[j-1] / a[j-1+(j-1)*lda]; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       if ( j != 1 ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         t = -b[j-1]; | 
					
						
							|  |  |  |         daxpy ( j-1, t, a+0+(j-1)*lda, 1, b, 1 ); | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Compute RSD or AB as required. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  |   if ( cr || cab ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     for ( jj = 1; jj <= ju; jj++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       j = ju - jj + 1; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       if ( qraux[j-1] != 0.0 ) | 
					
						
							|  |  |  |       { | 
					
						
							|  |  |  |         temp = a[j-1+(j-1)*lda]; | 
					
						
							|  |  |  |         a[j-1+(j-1)*lda] = qraux[j-1]; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |         if ( cr ) | 
					
						
							|  |  |  |         { | 
					
						
							|  |  |  |           t = -ddot ( n-j+1, a+j-1+(j-1)*lda, 1, rsd+j-1, 1 )  | 
					
						
							|  |  |  |             / a[j-1+(j-1)*lda]; | 
					
						
							|  |  |  |           daxpy ( n-j+1, t, a+j-1+(j-1)*lda, 1, rsd+j-1, 1 ); | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |         if ( cab ) | 
					
						
							|  |  |  |         { | 
					
						
							|  |  |  |           t = -ddot ( n-j+1, a+j-1+(j-1)*lda, 1, ab+j-1, 1 )  | 
					
						
							|  |  |  |             / a[j-1+(j-1)*lda]; | 
					
						
							|  |  |  |           daxpy ( n-j+1, t, a+j-1+(j-1)*lda, 1, ab+j-1, 1 ); | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  |         a[j-1+(j-1)*lda] = temp; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   return info; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | void dscal ( int n, double sa, double x[], int incx ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DSCAL scales a vector by a constant. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license.  | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     30 March 2007 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch, Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, 1979. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Charles Lawson, Richard Hanson, David Kincaid, Fred Krogh, | 
					
						
							|  |  |  |     Basic Linear Algebra Subprograms for Fortran Usage, | 
					
						
							|  |  |  |     Algorithm 539, | 
					
						
							|  |  |  |     ACM Transactions on Mathematical Software, | 
					
						
							|  |  |  |     Volume 5, Number 3, September 1979, pages 308-323. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of entries in the vector. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double SA, the multiplier. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, double X[*], the vector to be scaled. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCX, the increment between successive entries of X. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int i; | 
					
						
							|  |  |  |   int ix; | 
					
						
							|  |  |  |   int m; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( n <= 0 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   else if ( incx == 1 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     m = n % 5; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( i = 0; i < m; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       x[i] = sa * x[i]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( i = m; i < n; i = i + 5 ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       x[i]   = sa * x[i]; | 
					
						
							|  |  |  |       x[i+1] = sa * x[i+1]; | 
					
						
							|  |  |  |       x[i+2] = sa * x[i+2]; | 
					
						
							|  |  |  |       x[i+3] = sa * x[i+3]; | 
					
						
							|  |  |  |       x[i+4] = sa * x[i+4]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   else | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     if ( 0 <= incx ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       ix = 0; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     else | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       ix = ( - n + 1 ) * incx; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( i = 0; i < n; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       x[ix] = sa * x[ix]; | 
					
						
							|  |  |  |       ix = ix + incx; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | void dswap ( int n, double x[], int incx, double y[], int incy ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DSWAP interchanges two vectors. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license.  | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     30 March 2007 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch, Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, 1979. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Charles Lawson, Richard Hanson, David Kincaid, Fred Krogh, | 
					
						
							|  |  |  |     Basic Linear Algebra Subprograms for Fortran Usage, | 
					
						
							|  |  |  |     Algorithm 539,  | 
					
						
							|  |  |  |     ACM Transactions on Mathematical Software,  | 
					
						
							|  |  |  |     Volume 5, Number 3, September 1979, pages 308-323. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of entries in the vectors. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, double X[*], one of the vectors to swap. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCX, the increment between successive entries of X. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, double Y[*], one of the vectors to swap. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCY, the increment between successive elements of Y. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int i; | 
					
						
							|  |  |  |   int ix; | 
					
						
							|  |  |  |   int iy; | 
					
						
							|  |  |  |   int m; | 
					
						
							|  |  |  |   double temp; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if ( n <= 0 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   else if ( incx == 1 && incy == 1 ) | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     m = n % 3; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( i = 0; i < m; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       temp = x[i]; | 
					
						
							|  |  |  |       x[i] = y[i]; | 
					
						
							|  |  |  |       y[i] = temp; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( i = m; i < n; i = i + 3 ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       temp = x[i]; | 
					
						
							|  |  |  |       x[i] = y[i]; | 
					
						
							|  |  |  |       y[i] = temp; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       temp = x[i+1]; | 
					
						
							|  |  |  |       x[i+1] = y[i+1]; | 
					
						
							|  |  |  |       y[i+1] = temp; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       temp = x[i+2]; | 
					
						
							|  |  |  |       x[i+2] = y[i+2]; | 
					
						
							|  |  |  |       y[i+2] = temp; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   else | 
					
						
							|  |  |  |   { | 
					
						
							|  |  |  |     if ( 0 <= incx ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       ix = 0; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     else | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       ix = ( - n + 1 ) * incx; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     if ( 0 <= incy ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       iy = 0; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     else | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       iy = ( - n + 1 ) * incy; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     for ( i = 0; i < n; i++ ) | 
					
						
							|  |  |  |     { | 
					
						
							|  |  |  |       temp = x[ix]; | 
					
						
							|  |  |  |       x[ix] = y[iy]; | 
					
						
							|  |  |  |       y[iy] = temp; | 
					
						
							|  |  |  |       ix = ix + incx; | 
					
						
							|  |  |  |       iy = iy + incy; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   return; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | double *qr_solve ( int m, int n, double a[], double b[] ) | 
					
						
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							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /*
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							|  |  |  |   Purpose: | 
					
						
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							|  |  |  |     QR_SOLVE solves a linear system in the least squares sense. | 
					
						
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							|  |  |  |   Discussion: | 
					
						
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							|  |  |  |     If the matrix A has full column rank, then the solution X should be the | 
					
						
							|  |  |  |     unique vector that minimizes the Euclidean norm of the residual. | 
					
						
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							|  |  |  |     If the matrix A does not have full column rank, then the solution is | 
					
						
							|  |  |  |     not unique; the vector X will minimize the residual norm, but so will | 
					
						
							|  |  |  |     various other vectors. | 
					
						
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							|  |  |  |   Licensing: | 
					
						
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							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
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							|  |  |  |   Modified: | 
					
						
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							|  |  |  |     11 September 2012 | 
					
						
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							|  |  |  |   Author: | 
					
						
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							|  |  |  |     John Burkardt | 
					
						
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							|  |  |  |   Reference: | 
					
						
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							|  |  |  |     David Kahaner, Cleve Moler, Steven Nash, | 
					
						
							|  |  |  |     Numerical Methods and Software, | 
					
						
							|  |  |  |     Prentice Hall, 1989, | 
					
						
							|  |  |  |     ISBN: 0-13-627258-4, | 
					
						
							|  |  |  |     LC: TA345.K34. | 
					
						
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							|  |  |  |   Parameters: | 
					
						
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							|  |  |  |     Input, int M, the number of rows of A. | 
					
						
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							|  |  |  |     Input, int N, the number of columns of A. | 
					
						
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							|  |  |  |     Input, double A[M*N], the matrix. | 
					
						
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							|  |  |  |     Input, double B[M], the right hand side. | 
					
						
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							|  |  |  |     Output, double QR_SOLVE[N], the least squares solution. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   double *a_qr; | 
					
						
							|  |  |  |   int ind; | 
					
						
							|  |  |  |   int itask; | 
					
						
							|  |  |  |   int *jpvt; | 
					
						
							|  |  |  |   int kr; | 
					
						
							|  |  |  |   int lda; | 
					
						
							|  |  |  |   double *qraux; | 
					
						
							|  |  |  |   double *r; | 
					
						
							|  |  |  |   double tol; | 
					
						
							|  |  |  |   double *x; | 
					
						
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							|  |  |  |   a_qr = r8mat_copy_new ( m, n, a ); | 
					
						
							|  |  |  |   lda = m; | 
					
						
							|  |  |  |   tol = r8_epsilon ( ) / r8mat_amax ( m, n, a_qr ); | 
					
						
							|  |  |  |   x = ( double * ) malloc ( n * sizeof ( double ) ); | 
					
						
							|  |  |  |   jpvt = ( int * ) malloc ( n * sizeof ( int ) ); | 
					
						
							|  |  |  |   qraux = ( double * ) malloc ( n * sizeof ( double ) ); | 
					
						
							|  |  |  |   r = ( double * ) malloc ( m * sizeof ( double ) ); | 
					
						
							|  |  |  |   itask = 1; | 
					
						
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							|  |  |  |   ind = dqrls ( a_qr, lda, m, n, tol, &kr, b, x, r, jpvt, qraux, itask ); | 
					
						
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							|  |  |  |   free ( a_qr ); | 
					
						
							|  |  |  |   free ( jpvt ); | 
					
						
							|  |  |  |   free ( qraux );  | 
					
						
							|  |  |  |   free ( r ); | 
					
						
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							|  |  |  |   return x; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
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							|  |  |  | #endif
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