|  |  |  | /**
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							|  |  |  |  * Marlin 3D Printer Firmware | 
					
						
							|  |  |  |  * Copyright (C) 2016 MarlinFirmware [https://github.com/MarlinFirmware/Marlin]
 | 
					
						
							|  |  |  |  * | 
					
						
							|  |  |  |  * Based on Sprinter and grbl. | 
					
						
							|  |  |  |  * Copyright (C) 2011 Camiel Gubbels / Erik van der Zalm | 
					
						
							|  |  |  |  * | 
					
						
							|  |  |  |  * This program is free software: you can redistribute it and/or modify | 
					
						
							|  |  |  |  * it under the terms of the GNU General Public License as published by | 
					
						
							|  |  |  |  * the Free Software Foundation, either version 3 of the License, or | 
					
						
							|  |  |  |  * (at your option) any later version. | 
					
						
							|  |  |  |  * | 
					
						
							|  |  |  |  * This program is distributed in the hope that it will be useful, | 
					
						
							|  |  |  |  * but WITHOUT ANY WARRANTY; without even the implied warranty of | 
					
						
							|  |  |  |  * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the | 
					
						
							|  |  |  |  * GNU General Public License for more details. | 
					
						
							|  |  |  |  * | 
					
						
							|  |  |  |  * You should have received a copy of the GNU General Public License | 
					
						
							|  |  |  |  * along with this program.  If not, see <http://www.gnu.org/licenses/>.
 | 
					
						
							|  |  |  |  * | 
					
						
							|  |  |  |  */ | 
					
						
							|  |  |  | 
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							|  |  |  | #include "qr_solve.h"
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							|  |  |  | 
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							|  |  |  | #if ENABLED(AUTO_BED_LEVELING_GRID)
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							|  |  |  | 
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							|  |  |  | #include <stdlib.h>
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							|  |  |  | #include <math.h>
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							|  |  |  | 
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							|  |  |  | //# include "r8lib.h"
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							|  |  |  | 
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							|  |  |  | int i4_min(int i1, int i2) | 
					
						
							|  |  |  | 
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							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
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							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
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							|  |  |  |     I4_MIN returns the smaller of two I4's. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
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							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
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							|  |  |  |     29 August 2006 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
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							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
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							|  |  |  |     Input, int I1, I2, two integers to be compared. | 
					
						
							|  |  |  | 
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							|  |  |  |     Output, int I4_MIN, the smaller of I1 and I2. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   return (i1 < i2) ? i1 : i2; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
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							|  |  |  | double r8_epsilon(void) | 
					
						
							|  |  |  | 
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							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
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							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
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							|  |  |  |     R8_EPSILON returns the R8 round off unit. | 
					
						
							|  |  |  | 
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							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
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							|  |  |  |     R8_EPSILON is a number R which is a power of 2 with the property that, | 
					
						
							|  |  |  |     to the precision of the computer's arithmetic, | 
					
						
							|  |  |  |       1 < 1 + R | 
					
						
							|  |  |  |     but | 
					
						
							|  |  |  |       1 = ( 1 + R / 2 ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
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							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     01 September 2012 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
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							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
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							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
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							|  |  |  |     Output, double R8_EPSILON, the R8 round-off unit. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   const double value = 2.220446049250313E-016; | 
					
						
							|  |  |  |   return value; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
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							|  |  |  | double r8_max(double x, double y) | 
					
						
							|  |  |  | 
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							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
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							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
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							|  |  |  |     R8_MAX returns the maximum of two R8's. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     07 May 2006 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
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							|  |  |  |     Input, double X, Y, the quantities to compare. | 
					
						
							|  |  |  | 
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							|  |  |  |     Output, double R8_MAX, the maximum of X and Y. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   return (y < x) ? x : y; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
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							|  |  |  | double r8_abs(double x) | 
					
						
							|  |  |  | 
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							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
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							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
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							|  |  |  |     R8_ABS returns the absolute value of an R8. | 
					
						
							|  |  |  | 
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							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     07 May 2006 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
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							|  |  |  |     Input, double X, the quantity whose absolute value is desired. | 
					
						
							|  |  |  | 
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							|  |  |  |     Output, double R8_ABS, the absolute value of X. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   return (x < 0.0) ? -x : x; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
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							|  |  |  | double r8_sign(double x) | 
					
						
							|  |  |  | 
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							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
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							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
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							|  |  |  |     R8_SIGN returns the sign of an R8. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     08 May 2006 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
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							|  |  |  |     Input, double X, the number whose sign is desired. | 
					
						
							|  |  |  | 
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							|  |  |  |     Output, double R8_SIGN, the sign of X. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   return (x < 0.0) ? -1.0 : 1.0; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
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							|  |  |  | double r8mat_amax(int m, int n, double a[]) | 
					
						
							|  |  |  | 
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							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
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							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     R8MAT_AMAX returns the maximum absolute value entry of an R8MAT. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     An R8MAT is a doubly dimensioned array of R8 values, stored as a vector | 
					
						
							|  |  |  |     in column-major order. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     07 September 2012 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
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							|  |  |  |     Input, int M, the number of rows in A. | 
					
						
							|  |  |  | 
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							|  |  |  |     Input, int N, the number of columns in A. | 
					
						
							|  |  |  | 
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							|  |  |  |     Input, double A[M*N], the M by N matrix. | 
					
						
							|  |  |  | 
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							|  |  |  |     Output, double R8MAT_AMAX, the maximum absolute value entry of A. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   double value = r8_abs(a[0 + 0 * m]); | 
					
						
							|  |  |  |   for (int j = 0; j < n; j++) { | 
					
						
							|  |  |  |     for (int i = 0; i < m; i++) { | 
					
						
							|  |  |  |       NOLESS(value, r8_abs(a[i + j * m])); | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return value; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
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							|  |  |  | void r8mat_copy(double a2[], int m, int n, double a1[]) | 
					
						
							|  |  |  | 
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							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
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							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
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							|  |  |  |     R8MAT_COPY_NEW copies one R8MAT to a "new" R8MAT. | 
					
						
							|  |  |  | 
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							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     An R8MAT is a doubly dimensioned array of R8 values, stored as a vector | 
					
						
							|  |  |  |     in column-major order. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     26 July 2008 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
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							|  |  |  |     Input, int M, N, the number of rows and columns. | 
					
						
							|  |  |  | 
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							|  |  |  |     Input, double A1[M*N], the matrix to be copied. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double R8MAT_COPY_NEW[M*N], the copy of A1. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   for (int j = 0; j < n; j++) { | 
					
						
							|  |  |  |     for (int i = 0; i < m; i++) | 
					
						
							|  |  |  |       a2[i + j * m] = a1[i + j * m]; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | 
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							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
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							|  |  |  | void daxpy(int n, double da, double dx[], int incx, double dy[], int incy) | 
					
						
							|  |  |  | 
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							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
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							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
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							|  |  |  |     DAXPY computes constant times a vector plus a vector. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
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							|  |  |  |     This routine uses unrolled loops for increments equal to one. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     30 March 2007 | 
					
						
							|  |  |  | 
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							|  |  |  |   Author: | 
					
						
							|  |  |  | 
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							|  |  |  |     C version by John Burkardt | 
					
						
							|  |  |  | 
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							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch, Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, 1979. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Charles Lawson, Richard Hanson, David Kincaid, Fred Krogh, | 
					
						
							|  |  |  |     Basic Linear Algebra Subprograms for Fortran Usage, | 
					
						
							|  |  |  |     Algorithm 539, | 
					
						
							|  |  |  |     ACM Transactions on Mathematical Software, | 
					
						
							|  |  |  |     Volume 5, Number 3, September 1979, pages 308-323. | 
					
						
							|  |  |  | 
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							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of elements in DX and DY. | 
					
						
							|  |  |  | 
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							|  |  |  |     Input, double DA, the multiplier of DX. | 
					
						
							|  |  |  | 
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							|  |  |  |     Input, double DX[*], the first vector. | 
					
						
							|  |  |  | 
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							|  |  |  |     Input, int INCX, the increment between successive entries of DX. | 
					
						
							|  |  |  | 
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							|  |  |  |     Input/output, double DY[*], the second vector. | 
					
						
							|  |  |  |     On output, DY[*] has been replaced by DY[*] + DA * DX[*]. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCY, the increment between successive entries of DY. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   if (n <= 0 || da == 0.0) return; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   int i, ix, iy, m; | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Code for unequal increments or equal increments | 
					
						
							|  |  |  |     not equal to 1. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   if (incx != 1 || incy != 1) { | 
					
						
							|  |  |  |     if (0 <= incx) | 
					
						
							|  |  |  |       ix = 0; | 
					
						
							|  |  |  |     else | 
					
						
							|  |  |  |       ix = (- n + 1) * incx; | 
					
						
							|  |  |  |     if (0 <= incy) | 
					
						
							|  |  |  |       iy = 0; | 
					
						
							|  |  |  |     else | 
					
						
							|  |  |  |       iy = (- n + 1) * incy; | 
					
						
							|  |  |  |     for (i = 0; i < n; i++) { | 
					
						
							|  |  |  |       dy[iy] = dy[iy] + da * dx[ix]; | 
					
						
							|  |  |  |       ix = ix + incx; | 
					
						
							|  |  |  |       iy = iy + incy; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Code for both increments equal to 1. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   else { | 
					
						
							|  |  |  |     m = n % 4; | 
					
						
							|  |  |  |     for (i = 0; i < m; i++) | 
					
						
							|  |  |  |       dy[i] = dy[i] + da * dx[i]; | 
					
						
							|  |  |  |     for (i = m; i < n; i = i + 4) { | 
					
						
							|  |  |  |       dy[i  ] = dy[i  ] + da * dx[i  ]; | 
					
						
							|  |  |  |       dy[i + 1] = dy[i + 1] + da * dx[i + 1]; | 
					
						
							|  |  |  |       dy[i + 2] = dy[i + 2] + da * dx[i + 2]; | 
					
						
							|  |  |  |       dy[i + 3] = dy[i + 3] + da * dx[i + 3]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | double ddot(int n, double dx[], int incx, double dy[], int incy) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DDOT forms the dot product of two vectors. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This routine uses unrolled loops for increments equal to one. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     30 March 2007 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch, Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, 1979. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Charles Lawson, Richard Hanson, David Kincaid, Fred Krogh, | 
					
						
							|  |  |  |     Basic Linear Algebra Subprograms for Fortran Usage, | 
					
						
							|  |  |  |     Algorithm 539, | 
					
						
							|  |  |  |     ACM Transactions on Mathematical Software, | 
					
						
							|  |  |  |     Volume 5, Number 3, September 1979, pages 308-323. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of entries in the vectors. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double DX[*], the first vector. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCX, the increment between successive entries in DX. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double DY[*], the second vector. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCY, the increment between successive entries in DY. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double DDOT, the sum of the product of the corresponding | 
					
						
							|  |  |  |     entries of DX and DY. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if (n <= 0) return 0.0; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   int i, m; | 
					
						
							|  |  |  |   double dtemp = 0.0; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Code for unequal increments or equal increments | 
					
						
							|  |  |  |     not equal to 1. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   if (incx != 1 || incy != 1) { | 
					
						
							|  |  |  |     int ix = (incx >= 0) ? 0 : (-n + 1) * incx, | 
					
						
							|  |  |  |         iy = (incy >= 0) ? 0 : (-n + 1) * incy; | 
					
						
							|  |  |  |     for (i = 0; i < n; i++) { | 
					
						
							|  |  |  |       dtemp += dx[ix] * dy[iy]; | 
					
						
							|  |  |  |       ix = ix + incx; | 
					
						
							|  |  |  |       iy = iy + incy; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Code for both increments equal to 1. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   else { | 
					
						
							|  |  |  |     m = n % 5; | 
					
						
							|  |  |  |     for (i = 0; i < m; i++) | 
					
						
							|  |  |  |       dtemp += dx[i] * dy[i]; | 
					
						
							|  |  |  |     for (i = m; i < n; i = i + 5) { | 
					
						
							|  |  |  |       dtemp += dx[i] * dy[i] | 
					
						
							|  |  |  |               + dx[i + 1] * dy[i + 1] | 
					
						
							|  |  |  |               + dx[i + 2] * dy[i + 2] | 
					
						
							|  |  |  |               + dx[i + 3] * dy[i + 3] | 
					
						
							|  |  |  |               + dx[i + 4] * dy[i + 4]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return dtemp; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | double dnrm2(int n, double x[], int incx) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DNRM2 returns the euclidean norm of a vector. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |      DNRM2 ( X ) = sqrt ( X' * X ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     30 March 2007 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch, Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, 1979. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Charles Lawson, Richard Hanson, David Kincaid, Fred Krogh, | 
					
						
							|  |  |  |     Basic Linear Algebra Subprograms for Fortran Usage, | 
					
						
							|  |  |  |     Algorithm 539, | 
					
						
							|  |  |  |     ACM Transactions on Mathematical Software, | 
					
						
							|  |  |  |     Volume 5, Number 3, September 1979, pages 308-323. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of entries in the vector. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double X[*], the vector whose norm is to be computed. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCX, the increment between successive entries of X. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double DNRM2, the Euclidean norm of X. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   double norm; | 
					
						
							|  |  |  |   if (n < 1 || incx < 1) | 
					
						
							|  |  |  |     norm = 0.0; | 
					
						
							|  |  |  |   else if (n == 1) | 
					
						
							|  |  |  |     norm = r8_abs(x[0]); | 
					
						
							|  |  |  |   else { | 
					
						
							|  |  |  |     double scale = 0.0, ssq = 1.0; | 
					
						
							|  |  |  |     int ix = 0; | 
					
						
							|  |  |  |     for (int i = 0; i < n; i++) { | 
					
						
							|  |  |  |       if (x[ix] != 0.0) { | 
					
						
							|  |  |  |         double absxi = r8_abs(x[ix]); | 
					
						
							|  |  |  |         if (scale < absxi) { | 
					
						
							|  |  |  |           ssq = 1.0 + ssq * (scale / absxi) * (scale / absxi); | 
					
						
							|  |  |  |           scale = absxi; | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  |         else | 
					
						
							|  |  |  |           ssq = ssq + (absxi / scale) * (absxi / scale); | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |       ix += incx; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     norm = scale * sqrt(ssq); | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return norm; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | void dqrank(double a[], int lda, int m, int n, double tol, int* kr, | 
					
						
							|  |  |  |             int jpvt[], double qraux[]) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRANK computes the QR factorization of a rectangular matrix. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This routine is used in conjunction with DQRLSS to solve | 
					
						
							|  |  |  |     overdetermined, underdetermined and singular linear systems | 
					
						
							|  |  |  |     in a least squares sense. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRANK uses the LINPACK subroutine DQRDC to compute the QR | 
					
						
							|  |  |  |     factorization, with column pivoting, of an M by N matrix A. | 
					
						
							|  |  |  |     The numerical rank is determined using the tolerance TOL. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Note that on output, ABS ( A(1,1) ) / ABS ( A(KR,KR) ) is an estimate | 
					
						
							|  |  |  |     of the condition number of the matrix of independent columns, | 
					
						
							|  |  |  |     and of R.  This estimate will be <= 1/TOL. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     21 April 2012 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch, Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, 1979, | 
					
						
							|  |  |  |     ISBN13: 978-0-898711-72-1, | 
					
						
							|  |  |  |     LC: QA214.L56. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, double A[LDA*N].  On input, the matrix whose | 
					
						
							|  |  |  |     decomposition is to be computed.  On output, the information from DQRDC. | 
					
						
							|  |  |  |     The triangular matrix R of the QR factorization is contained in the | 
					
						
							|  |  |  |     upper triangle and information needed to recover the orthogonal | 
					
						
							|  |  |  |     matrix Q is stored below the diagonal in A and in the vector QRAUX. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int LDA, the leading dimension of A, which must | 
					
						
							|  |  |  |     be at least M. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int M, the number of rows of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of columns of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double TOL, a relative tolerance used to determine the | 
					
						
							|  |  |  |     numerical rank.  The problem should be scaled so that all the elements | 
					
						
							|  |  |  |     of A have roughly the same absolute accuracy, EPS.  Then a reasonable | 
					
						
							|  |  |  |     value for TOL is roughly EPS divided by the magnitude of the largest | 
					
						
							|  |  |  |     element. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, int *KR, the numerical rank. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, int JPVT[N], the pivot information from DQRDC. | 
					
						
							|  |  |  |     Columns JPVT(1), ..., JPVT(KR) of the original matrix are linearly | 
					
						
							|  |  |  |     independent to within the tolerance TOL and the remaining columns | 
					
						
							|  |  |  |     are linearly dependent. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double QRAUX[N], will contain extra information defining | 
					
						
							|  |  |  |     the QR factorization. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   double work[n]; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   for (int i = 0; i < n; i++) | 
					
						
							|  |  |  |     jpvt[i] = 0; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   int job = 1; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   dqrdc(a, lda, m, n, qraux, jpvt, work, job); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   *kr = 0; | 
					
						
							|  |  |  |   int k = i4_min(m, n); | 
					
						
							|  |  |  |   for (int j = 0; j < k; j++) { | 
					
						
							|  |  |  |     if (r8_abs(a[j + j * lda]) <= tol * r8_abs(a[0 + 0 * lda])) | 
					
						
							|  |  |  |       return; | 
					
						
							|  |  |  |     *kr = j + 1; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | void dqrdc(double a[], int lda, int n, int p, double qraux[], int jpvt[], | 
					
						
							|  |  |  |            double work[], int job) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRDC computes the QR factorization of a real rectangular matrix. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRDC uses Householder transformations. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Column pivoting based on the 2-norms of the reduced columns may be | 
					
						
							|  |  |  |     performed at the user's option. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     07 June 2005 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch and Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, (Society for Industrial and Applied Mathematics), | 
					
						
							|  |  |  |     3600 University City Science Center, | 
					
						
							|  |  |  |     Philadelphia, PA, 19104-2688. | 
					
						
							|  |  |  |     ISBN 0-89871-172-X | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, double A(LDA,P).  On input, the N by P matrix | 
					
						
							|  |  |  |     whose decomposition is to be computed.  On output, A contains in | 
					
						
							|  |  |  |     its upper triangle the upper triangular matrix R of the QR | 
					
						
							|  |  |  |     factorization.  Below its diagonal A contains information from | 
					
						
							|  |  |  |     which the orthogonal part of the decomposition can be recovered. | 
					
						
							|  |  |  |     Note that if pivoting has been requested, the decomposition is not that | 
					
						
							|  |  |  |     of the original matrix A but that of A with its columns permuted | 
					
						
							|  |  |  |     as described by JPVT. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int LDA, the leading dimension of the array A.  LDA must | 
					
						
							|  |  |  |     be at least N. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of rows of the matrix A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int P, the number of columns of the matrix A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double QRAUX[P], contains further information required | 
					
						
							|  |  |  |     to recover the orthogonal part of the decomposition. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, integer JPVT[P].  On input, JPVT contains integers that | 
					
						
							|  |  |  |     control the selection of the pivot columns.  The K-th column A(*,K) of A | 
					
						
							|  |  |  |     is placed in one of three classes according to the value of JPVT(K). | 
					
						
							|  |  |  |       > 0, then A(K) is an initial column. | 
					
						
							|  |  |  |       = 0, then A(K) is a free column. | 
					
						
							|  |  |  |       < 0, then A(K) is a final column. | 
					
						
							|  |  |  |     Before the decomposition is computed, initial columns are moved to | 
					
						
							|  |  |  |     the beginning of the array A and final columns to the end.  Both | 
					
						
							|  |  |  |     initial and final columns are frozen in place during the computation | 
					
						
							|  |  |  |     and only free columns are moved.  At the K-th stage of the | 
					
						
							|  |  |  |     reduction, if A(*,K) is occupied by a free column it is interchanged | 
					
						
							|  |  |  |     with the free column of largest reduced norm.  JPVT is not referenced | 
					
						
							|  |  |  |     if JOB == 0.  On output, JPVT(K) contains the index of the column of the | 
					
						
							|  |  |  |     original matrix that has been interchanged into the K-th column, if | 
					
						
							|  |  |  |     pivoting was requested. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Workspace, double WORK[P].  WORK is not referenced if JOB == 0. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int JOB, initiates column pivoting. | 
					
						
							|  |  |  |     0, no pivoting is done. | 
					
						
							|  |  |  |     nonzero, pivoting is done. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int jp; | 
					
						
							|  |  |  |   int j; | 
					
						
							|  |  |  |   int lup; | 
					
						
							|  |  |  |   int maxj; | 
					
						
							|  |  |  |   double maxnrm, nrmxl, t, tt; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   int pl = 1, pu = 0; | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     If pivoting is requested, rearrange the columns. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   if (job != 0) { | 
					
						
							|  |  |  |     for (j = 1; j <= p; j++) { | 
					
						
							|  |  |  |       int swapj = (0 < jpvt[j - 1]); | 
					
						
							|  |  |  |       jpvt[j - 1] = (jpvt[j - 1] < 0) ? -j : j; | 
					
						
							|  |  |  |       if (swapj) { | 
					
						
							|  |  |  |         if (j != pl) | 
					
						
							|  |  |  |           dswap(n, a + 0 + (pl - 1)*lda, 1, a + 0 + (j - 1), 1); | 
					
						
							|  |  |  |         jpvt[j - 1] = jpvt[pl - 1]; | 
					
						
							|  |  |  |         jpvt[pl - 1] = j; | 
					
						
							|  |  |  |         pl++; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     pu = p; | 
					
						
							|  |  |  |     for (j = p; 1 <= j; j--) { | 
					
						
							|  |  |  |       if (jpvt[j - 1] < 0) { | 
					
						
							|  |  |  |         jpvt[j - 1] = -jpvt[j - 1]; | 
					
						
							|  |  |  |         if (j != pu) { | 
					
						
							|  |  |  |           dswap(n, a + 0 + (pu - 1)*lda, 1, a + 0 + (j - 1)*lda, 1); | 
					
						
							|  |  |  |           jp = jpvt[pu - 1]; | 
					
						
							|  |  |  |           jpvt[pu - 1] = jpvt[j - 1]; | 
					
						
							|  |  |  |           jpvt[j - 1] = jp; | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  |         pu = pu - 1; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Compute the norms of the free columns. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   for (j = pl; j <= pu; j++) | 
					
						
							|  |  |  |     qraux[j - 1] = dnrm2(n, a + 0 + (j - 1) * lda, 1); | 
					
						
							|  |  |  |   for (j = pl; j <= pu; j++) | 
					
						
							|  |  |  |     work[j - 1] = qraux[j - 1]; | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Perform the Householder reduction of A. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   lup = i4_min(n, p); | 
					
						
							|  |  |  |   for (int l = 1; l <= lup; l++) { | 
					
						
							|  |  |  |     /**
 | 
					
						
							|  |  |  |       Bring the column of largest norm into the pivot position. | 
					
						
							|  |  |  |     */ | 
					
						
							|  |  |  |     if (pl <= l && l < pu) { | 
					
						
							|  |  |  |       maxnrm = 0.0; | 
					
						
							|  |  |  |       maxj = l; | 
					
						
							|  |  |  |       for (j = l; j <= pu; j++) { | 
					
						
							|  |  |  |         if (maxnrm < qraux[j - 1]) { | 
					
						
							|  |  |  |           maxnrm = qraux[j - 1]; | 
					
						
							|  |  |  |           maxj = j; | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |       if (maxj != l) { | 
					
						
							|  |  |  |         dswap(n, a + 0 + (l - 1)*lda, 1, a + 0 + (maxj - 1)*lda, 1); | 
					
						
							|  |  |  |         qraux[maxj - 1] = qraux[l - 1]; | 
					
						
							|  |  |  |         work[maxj - 1] = work[l - 1]; | 
					
						
							|  |  |  |         jp = jpvt[maxj - 1]; | 
					
						
							|  |  |  |         jpvt[maxj - 1] = jpvt[l - 1]; | 
					
						
							|  |  |  |         jpvt[l - 1] = jp; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     /**
 | 
					
						
							|  |  |  |       Compute the Householder transformation for column L. | 
					
						
							|  |  |  |     */ | 
					
						
							|  |  |  |     qraux[l - 1] = 0.0; | 
					
						
							|  |  |  |     if (l != n) { | 
					
						
							|  |  |  |       nrmxl = dnrm2(n - l + 1, a + l - 1 + (l - 1) * lda, 1); | 
					
						
							|  |  |  |       if (nrmxl != 0.0) { | 
					
						
							|  |  |  |         if (a[l - 1 + (l - 1)*lda] != 0.0) | 
					
						
							|  |  |  |           nrmxl = nrmxl * r8_sign(a[l - 1 + (l - 1) * lda]); | 
					
						
							|  |  |  |         dscal(n - l + 1, 1.0 / nrmxl, a + l - 1 + (l - 1)*lda, 1); | 
					
						
							|  |  |  |         a[l - 1 + (l - 1)*lda] = 1.0 + a[l - 1 + (l - 1) * lda]; | 
					
						
							|  |  |  |         /**
 | 
					
						
							|  |  |  |           Apply the transformation to the remaining columns, updating the norms. | 
					
						
							|  |  |  |         */ | 
					
						
							|  |  |  |         for (j = l + 1; j <= p; j++) { | 
					
						
							|  |  |  |           t = -ddot(n - l + 1, a + l - 1 + (l - 1) * lda, 1, a + l - 1 + (j - 1) * lda, 1) | 
					
						
							|  |  |  |               / a[l - 1 + (l - 1) * lda]; | 
					
						
							|  |  |  |           daxpy(n - l + 1, t, a + l - 1 + (l - 1)*lda, 1, a + l - 1 + (j - 1)*lda, 1); | 
					
						
							|  |  |  |           if (pl <= j && j <= pu) { | 
					
						
							|  |  |  |             if (qraux[j - 1] != 0.0) { | 
					
						
							|  |  |  |               tt = 1.0 - pow(r8_abs(a[l - 1 + (j - 1) * lda]) / qraux[j - 1], 2); | 
					
						
							|  |  |  |               tt = r8_max(tt, 0.0); | 
					
						
							|  |  |  |               t = tt; | 
					
						
							|  |  |  |               tt = 1.0 + 0.05 * tt * pow(qraux[j - 1] / work[j - 1], 2); | 
					
						
							|  |  |  |               if (tt != 1.0) | 
					
						
							|  |  |  |                 qraux[j - 1] = qraux[j - 1] * sqrt(t); | 
					
						
							|  |  |  |               else { | 
					
						
							|  |  |  |                 qraux[j - 1] = dnrm2(n - l, a + l + (j - 1) * lda, 1); | 
					
						
							|  |  |  |                 work[j - 1] = qraux[j - 1]; | 
					
						
							|  |  |  |               } | 
					
						
							|  |  |  |             } | 
					
						
							|  |  |  |           } | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  |         /**
 | 
					
						
							|  |  |  |           Save the transformation. | 
					
						
							|  |  |  |         */ | 
					
						
							|  |  |  |         qraux[l - 1] = a[l - 1 + (l - 1) * lda]; | 
					
						
							|  |  |  |         a[l - 1 + (l - 1)*lda] = -nrmxl; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | int dqrls(double a[], int lda, int m, int n, double tol, int* kr, double b[], | 
					
						
							|  |  |  |           double x[], double rsd[], int jpvt[], double qraux[], int itask) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRLS factors and solves a linear system in the least squares sense. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     The linear system may be overdetermined, underdetermined or singular. | 
					
						
							|  |  |  |     The solution is obtained using a QR factorization of the | 
					
						
							|  |  |  |     coefficient matrix. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRLS can be efficiently used to solve several least squares | 
					
						
							|  |  |  |     problems with the same matrix A.  The first system is solved | 
					
						
							|  |  |  |     with ITASK = 1.  The subsequent systems are solved with | 
					
						
							|  |  |  |     ITASK = 2, to avoid the recomputation of the matrix factors. | 
					
						
							|  |  |  |     The parameters KR, JPVT, and QRAUX must not be modified | 
					
						
							|  |  |  |     between calls to DQRLS. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRLS is used to solve in a least squares sense | 
					
						
							|  |  |  |     overdetermined, underdetermined and singular linear systems. | 
					
						
							|  |  |  |     The system is A*X approximates B where A is M by N. | 
					
						
							|  |  |  |     B is a given M-vector, and X is the N-vector to be computed. | 
					
						
							|  |  |  |     A solution X is found which minimimzes the sum of squares (2-norm) | 
					
						
							|  |  |  |     of the residual,  A*X - B. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     The numerical rank of A is determined using the tolerance TOL. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRLS uses the LINPACK subroutine DQRDC to compute the QR | 
					
						
							|  |  |  |     factorization, with column pivoting, of an M by N matrix A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     10 September 2012 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     David Kahaner, Cleve Moler, Steven Nash, | 
					
						
							|  |  |  |     Numerical Methods and Software, | 
					
						
							|  |  |  |     Prentice Hall, 1989, | 
					
						
							|  |  |  |     ISBN: 0-13-627258-4, | 
					
						
							|  |  |  |     LC: TA345.K34. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, double A[LDA*N], an M by N matrix. | 
					
						
							|  |  |  |     On input, the matrix whose decomposition is to be computed. | 
					
						
							|  |  |  |     In a least squares data fitting problem, A(I,J) is the | 
					
						
							|  |  |  |     value of the J-th basis (model) function at the I-th data point. | 
					
						
							|  |  |  |     On output, A contains the output from DQRDC.  The triangular matrix R | 
					
						
							|  |  |  |     of the QR factorization is contained in the upper triangle and | 
					
						
							|  |  |  |     information needed to recover the orthogonal matrix Q is stored | 
					
						
							|  |  |  |     below the diagonal in A and in the vector QRAUX. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int LDA, the leading dimension of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int M, the number of rows of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of columns of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double TOL, a relative tolerance used to determine the | 
					
						
							|  |  |  |     numerical rank.  The problem should be scaled so that all the elements | 
					
						
							|  |  |  |     of A have roughly the same absolute accuracy EPS.  Then a reasonable | 
					
						
							|  |  |  |     value for TOL is roughly EPS divided by the magnitude of the largest | 
					
						
							|  |  |  |     element. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, int *KR, the numerical rank. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double B[M], the right hand side of the linear system. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double X[N], a least squares solution to the linear | 
					
						
							|  |  |  |     system. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double RSD[M], the residual, B - A*X.  RSD may | 
					
						
							|  |  |  |     overwrite B. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Workspace, int JPVT[N], required if ITASK = 1. | 
					
						
							|  |  |  |     Columns JPVT(1), ..., JPVT(KR) of the original matrix are linearly | 
					
						
							|  |  |  |     independent to within the tolerance TOL and the remaining columns | 
					
						
							|  |  |  |     are linearly dependent.  ABS ( A(1,1) ) / ABS ( A(KR,KR) ) is an estimate | 
					
						
							|  |  |  |     of the condition number of the matrix of independent columns, | 
					
						
							|  |  |  |     and of R.  This estimate will be <= 1/TOL. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Workspace, double QRAUX[N], required if ITASK = 1. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int ITASK. | 
					
						
							|  |  |  |     1, DQRLS factors the matrix A and solves the least squares problem. | 
					
						
							|  |  |  |     2, DQRLS assumes that the matrix A was factored with an earlier | 
					
						
							|  |  |  |        call to DQRLS, and only solves the least squares problem. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, int DQRLS, error code. | 
					
						
							|  |  |  |     0:  no error | 
					
						
							|  |  |  |     -1: LDA < M   (fatal error) | 
					
						
							|  |  |  |     -2: N < 1     (fatal error) | 
					
						
							|  |  |  |     -3: ITASK < 1 (fatal error) | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int ind; | 
					
						
							|  |  |  |   if (lda < m) { | 
					
						
							|  |  |  |     /*fprintf ( stderr, "\n" );
 | 
					
						
							|  |  |  |     fprintf ( stderr, "DQRLS - Fatal error!\n" ); | 
					
						
							|  |  |  |     fprintf ( stderr, "  LDA < M.\n" );*/ | 
					
						
							|  |  |  |     ind = -1; | 
					
						
							|  |  |  |     return ind; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if (n <= 0) { | 
					
						
							|  |  |  |     /*fprintf ( stderr, "\n" );
 | 
					
						
							|  |  |  |     fprintf ( stderr, "DQRLS - Fatal error!\n" ); | 
					
						
							|  |  |  |     fprintf ( stderr, "  N <= 0.\n" );*/ | 
					
						
							|  |  |  |     ind = -2; | 
					
						
							|  |  |  |     return ind; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if (itask < 1) { | 
					
						
							|  |  |  |     /*fprintf ( stderr, "\n" );
 | 
					
						
							|  |  |  |     fprintf ( stderr, "DQRLS - Fatal error!\n" ); | 
					
						
							|  |  |  |     fprintf ( stderr, "  ITASK < 1.\n" );*/ | 
					
						
							|  |  |  |     ind = -3; | 
					
						
							|  |  |  |     return ind; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   ind = 0; | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Factor the matrix. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   if (itask == 1) | 
					
						
							|  |  |  |     dqrank(a, lda, m, n, tol, kr, jpvt, qraux); | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Solve the least-squares problem. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   dqrlss(a, lda, m, n, *kr, b, x, rsd, jpvt, qraux); | 
					
						
							|  |  |  |   return ind; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | void dqrlss(double a[], int lda, int m, int n, int kr, double b[], double x[], | 
					
						
							|  |  |  |             double rsd[], int jpvt[], double qraux[]) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRLSS solves a linear system in a least squares sense. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRLSS must be preceded by a call to DQRANK. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     The system is to be solved is | 
					
						
							|  |  |  |       A * X = B | 
					
						
							|  |  |  |     where | 
					
						
							|  |  |  |       A is an M by N matrix with rank KR, as determined by DQRANK, | 
					
						
							|  |  |  |       B is a given M-vector, | 
					
						
							|  |  |  |       X is the N-vector to be computed. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     A solution X, with at most KR nonzero components, is found which | 
					
						
							|  |  |  |     minimizes the 2-norm of the residual (A*X-B). | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Once the matrix A has been formed, DQRANK should be | 
					
						
							|  |  |  |     called once to decompose it.  Then, for each right hand | 
					
						
							|  |  |  |     side B, DQRLSS should be called once to obtain the | 
					
						
							|  |  |  |     solution and residual. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     10 September 2012 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double A[LDA*N], the QR factorization information | 
					
						
							|  |  |  |     from DQRANK.  The triangular matrix R of the QR factorization is | 
					
						
							|  |  |  |     contained in the upper triangle and information needed to recover | 
					
						
							|  |  |  |     the orthogonal matrix Q is stored below the diagonal in A and in | 
					
						
							|  |  |  |     the vector QRAUX. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int LDA, the leading dimension of A, which must | 
					
						
							|  |  |  |     be at least M. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int M, the number of rows of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of columns of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int KR, the rank of the matrix, as estimated by DQRANK. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double B[M], the right hand side of the linear system. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double X[N], a least squares solution to the | 
					
						
							|  |  |  |     linear system. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double RSD[M], the residual, B - A*X.  RSD may | 
					
						
							|  |  |  |     overwrite B. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int JPVT[N], the pivot information from DQRANK. | 
					
						
							|  |  |  |     Columns JPVT[0], ..., JPVT[KR-1] of the original matrix are linearly | 
					
						
							|  |  |  |     independent to within the tolerance TOL and the remaining columns | 
					
						
							|  |  |  |     are linearly dependent. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double QRAUX[N], auxiliary information from DQRANK | 
					
						
							|  |  |  |     defining the QR factorization. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int i; | 
					
						
							|  |  |  |   int info; | 
					
						
							|  |  |  |   int j; | 
					
						
							|  |  |  |   int job; | 
					
						
							|  |  |  |   int k; | 
					
						
							|  |  |  |   double t; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if (kr != 0) { | 
					
						
							|  |  |  |     job = 110; | 
					
						
							|  |  |  |     info = dqrsl(a, lda, m, kr, qraux, b, rsd, rsd, x, rsd, rsd, job); UNUSED(info); | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   for (i = 0; i < n; i++) | 
					
						
							|  |  |  |     jpvt[i] = - jpvt[i]; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   for (i = kr; i < n; i++) | 
					
						
							|  |  |  |     x[i] = 0.0; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   for (j = 1; j <= n; j++) { | 
					
						
							|  |  |  |     if (jpvt[j - 1] <= 0) { | 
					
						
							|  |  |  |       k = - jpvt[j - 1]; | 
					
						
							|  |  |  |       jpvt[j - 1] = k; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       while (k != j) { | 
					
						
							|  |  |  |         t = x[j - 1]; | 
					
						
							|  |  |  |         x[j - 1] = x[k - 1]; | 
					
						
							|  |  |  |         x[k - 1] = t; | 
					
						
							|  |  |  |         jpvt[k - 1] = -jpvt[k - 1]; | 
					
						
							|  |  |  |         k = jpvt[k - 1]; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | int dqrsl(double a[], int lda, int n, int k, double qraux[], double y[], | 
					
						
							|  |  |  |           double qy[], double qty[], double b[], double rsd[], double ab[], int job) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRSL computes transformations, projections, and least squares solutions. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DQRSL requires the output of DQRDC. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     For K <= min(N,P), let AK be the matrix | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       AK = ( A(JPVT[0]), A(JPVT(2)), ..., A(JPVT(K)) ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     formed from columns JPVT[0], ..., JPVT(K) of the original | 
					
						
							|  |  |  |     N by P matrix A that was input to DQRDC.  If no pivoting was | 
					
						
							|  |  |  |     done, AK consists of the first K columns of A in their | 
					
						
							|  |  |  |     original order.  DQRDC produces a factored orthogonal matrix Q | 
					
						
							|  |  |  |     and an upper triangular matrix R such that | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       AK = Q * (R) | 
					
						
							|  |  |  |                (0) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This information is contained in coded form in the arrays | 
					
						
							|  |  |  |     A and QRAUX. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     The parameters QY, QTY, B, RSD, and AB are not referenced | 
					
						
							|  |  |  |     if their computation is not requested and in this case | 
					
						
							|  |  |  |     can be replaced by dummy variables in the calling program. | 
					
						
							|  |  |  |     To save storage, the user may in some cases use the same | 
					
						
							|  |  |  |     array for different parameters in the calling sequence.  A | 
					
						
							|  |  |  |     frequently occurring example is when one wishes to compute | 
					
						
							|  |  |  |     any of B, RSD, or AB and does not need Y or QTY.  In this | 
					
						
							|  |  |  |     case one may identify Y, QTY, and one of B, RSD, or AB, while | 
					
						
							|  |  |  |     providing separate arrays for anything else that is to be | 
					
						
							|  |  |  |     computed. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Thus the calling sequence | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       dqrsl ( a, lda, n, k, qraux, y, dum, y, b, y, dum, 110, info ) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     will result in the computation of B and RSD, with RSD | 
					
						
							|  |  |  |     overwriting Y.  More generally, each item in the following | 
					
						
							|  |  |  |     list contains groups of permissible identifications for | 
					
						
							|  |  |  |     a single calling sequence. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       1. (Y,QTY,B) (RSD) (AB) (QY) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       2. (Y,QTY,RSD) (B) (AB) (QY) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       3. (Y,QTY,AB) (B) (RSD) (QY) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       4. (Y,QY) (QTY,B) (RSD) (AB) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       5. (Y,QY) (QTY,RSD) (B) (AB) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       6. (Y,QY) (QTY,AB) (B) (RSD) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     In any group the value returned in the array allocated to | 
					
						
							|  |  |  |     the group corresponds to the last member of the group. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     07 June 2005 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch and Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, (Society for Industrial and Applied Mathematics), | 
					
						
							|  |  |  |     3600 University City Science Center, | 
					
						
							|  |  |  |     Philadelphia, PA, 19104-2688. | 
					
						
							|  |  |  |     ISBN 0-89871-172-X | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double A[LDA*P], contains the output of DQRDC. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int LDA, the leading dimension of the array A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of rows of the matrix AK.  It must | 
					
						
							|  |  |  |     have the same value as N in DQRDC. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int K, the number of columns of the matrix AK.  K | 
					
						
							|  |  |  |     must not be greater than min(N,P), where P is the same as in the | 
					
						
							|  |  |  |     calling sequence to DQRDC. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double QRAUX[P], the auxiliary output from DQRDC. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double Y[N], a vector to be manipulated by DQRSL. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double QY[N], contains Q * Y, if requested. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double QTY[N], contains Q' * Y, if requested. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double B[K], the solution of the least squares problem | 
					
						
							|  |  |  |       minimize norm2 ( Y - AK * B), | 
					
						
							|  |  |  |     if its computation has been requested.  Note that if pivoting was | 
					
						
							|  |  |  |     requested in DQRDC, the J-th component of B will be associated with | 
					
						
							|  |  |  |     column JPVT(J) of the original matrix A that was input into DQRDC. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double RSD[N], the least squares residual Y - AK * B, | 
					
						
							|  |  |  |     if its computation has been requested.  RSD is also the orthogonal | 
					
						
							|  |  |  |     projection of Y onto the orthogonal complement of the column space | 
					
						
							|  |  |  |     of AK. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double AB[N], the least squares approximation Ak * B, | 
					
						
							|  |  |  |     if its computation has been requested.  AB is also the orthogonal | 
					
						
							|  |  |  |     projection of Y onto the column space of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, integer JOB, specifies what is to be computed.  JOB has | 
					
						
							|  |  |  |     the decimal expansion ABCDE, with the following meaning: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |       if A != 0, compute QY. | 
					
						
							|  |  |  |       if B != 0, compute QTY. | 
					
						
							|  |  |  |       if C != 0, compute QTY and B. | 
					
						
							|  |  |  |       if D != 0, compute QTY and RSD. | 
					
						
							|  |  |  |       if E != 0, compute QTY and AB. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Note that a request to compute B, RSD, or AB automatically triggers | 
					
						
							|  |  |  |     the computation of QTY, for which an array must be provided in the | 
					
						
							|  |  |  |     calling sequence. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, int DQRSL, is zero unless the computation of B has | 
					
						
							|  |  |  |     been requested and R is exactly singular.  In this case, INFO is the | 
					
						
							|  |  |  |     index of the first zero diagonal element of R, and B is left unaltered. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int cab; | 
					
						
							|  |  |  |   int cb; | 
					
						
							|  |  |  |   int cqty; | 
					
						
							|  |  |  |   int cqy; | 
					
						
							|  |  |  |   int cr; | 
					
						
							|  |  |  |   int i; | 
					
						
							|  |  |  |   int info; | 
					
						
							|  |  |  |   int j; | 
					
						
							|  |  |  |   int jj; | 
					
						
							|  |  |  |   int ju; | 
					
						
							|  |  |  |   double t; | 
					
						
							|  |  |  |   double temp; | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Set INFO flag. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   info = 0; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Determine what is to be computed. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   cqy  = ( job / 10000        != 0); | 
					
						
							|  |  |  |   cqty = ((job % 10000)       != 0); | 
					
						
							|  |  |  |   cb   = ((job %  1000) / 100 != 0); | 
					
						
							|  |  |  |   cr   = ((job %   100) /  10 != 0); | 
					
						
							|  |  |  |   cab  = ((job %    10)       != 0); | 
					
						
							|  |  |  |   ju = i4_min(k, n - 1); | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Special action when N = 1. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   if (ju == 0) { | 
					
						
							|  |  |  |     if (cqy) | 
					
						
							|  |  |  |       qy[0] = y[0]; | 
					
						
							|  |  |  |     if (cqty) | 
					
						
							|  |  |  |       qty[0] = y[0]; | 
					
						
							|  |  |  |     if (cab) | 
					
						
							|  |  |  |       ab[0] = y[0]; | 
					
						
							|  |  |  |     if (cb) { | 
					
						
							|  |  |  |       if (a[0 + 0 * lda] == 0.0) | 
					
						
							|  |  |  |         info = 1; | 
					
						
							|  |  |  |       else | 
					
						
							|  |  |  |         b[0] = y[0] / a[0 + 0 * lda]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     if (cr) | 
					
						
							|  |  |  |       rsd[0] = 0.0; | 
					
						
							|  |  |  |     return info; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Set up to compute QY or QTY. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   if (cqy) { | 
					
						
							|  |  |  |     for (i = 1; i <= n; i++) | 
					
						
							|  |  |  |       qy[i - 1] = y[i - 1]; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   if (cqty) { | 
					
						
							|  |  |  |     for (i = 1; i <= n; i++) | 
					
						
							|  |  |  |       qty[i - 1] = y[i - 1]; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Compute QY. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   if (cqy) { | 
					
						
							|  |  |  |     for (jj = 1; jj <= ju; jj++) { | 
					
						
							|  |  |  |       j = ju - jj + 1; | 
					
						
							|  |  |  |       if (qraux[j - 1] != 0.0) { | 
					
						
							|  |  |  |         temp = a[j - 1 + (j - 1) * lda]; | 
					
						
							|  |  |  |         a[j - 1 + (j - 1)*lda] = qraux[j - 1]; | 
					
						
							|  |  |  |         t = -ddot(n - j + 1, a + j - 1 + (j - 1) * lda, 1, qy + j - 1, 1) / a[j - 1 + (j - 1) * lda]; | 
					
						
							|  |  |  |         daxpy(n - j + 1, t, a + j - 1 + (j - 1)*lda, 1, qy + j - 1, 1); | 
					
						
							|  |  |  |         a[j - 1 + (j - 1)*lda] = temp; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Compute Q'*Y. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   if (cqty) { | 
					
						
							|  |  |  |     for (j = 1; j <= ju; j++) { | 
					
						
							|  |  |  |       if (qraux[j - 1] != 0.0) { | 
					
						
							|  |  |  |         temp = a[j - 1 + (j - 1) * lda]; | 
					
						
							|  |  |  |         a[j - 1 + (j - 1)*lda] = qraux[j - 1]; | 
					
						
							|  |  |  |         t = -ddot(n - j + 1, a + j - 1 + (j - 1) * lda, 1, qty + j - 1, 1) / a[j - 1 + (j - 1) * lda]; | 
					
						
							|  |  |  |         daxpy(n - j + 1, t, a + j - 1 + (j - 1)*lda, 1, qty + j - 1, 1); | 
					
						
							|  |  |  |         a[j - 1 + (j - 1)*lda] = temp; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Set up to compute B, RSD, or AB. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   if (cb) { | 
					
						
							|  |  |  |     for (i = 1; i <= k; i++) | 
					
						
							|  |  |  |       b[i - 1] = qty[i - 1]; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   if (cab) { | 
					
						
							|  |  |  |     for (i = 1; i <= k; i++) | 
					
						
							|  |  |  |       ab[i - 1] = qty[i - 1]; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   if (cr && k < n) { | 
					
						
							|  |  |  |     for (i = k + 1; i <= n; i++) | 
					
						
							|  |  |  |       rsd[i - 1] = qty[i - 1]; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   if (cab && k + 1 <= n) { | 
					
						
							|  |  |  |     for (i = k + 1; i <= n; i++) | 
					
						
							|  |  |  |       ab[i - 1] = 0.0; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   if (cr) { | 
					
						
							|  |  |  |     for (i = 1; i <= k; i++) | 
					
						
							|  |  |  |       rsd[i - 1] = 0.0; | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Compute B. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   if (cb) { | 
					
						
							|  |  |  |     for (jj = 1; jj <= k; jj++) { | 
					
						
							|  |  |  |       j = k - jj + 1; | 
					
						
							|  |  |  |       if (a[j - 1 + (j - 1)*lda] == 0.0) { | 
					
						
							|  |  |  |         info = j; | 
					
						
							|  |  |  |         break; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |       b[j - 1] = b[j - 1] / a[j - 1 + (j - 1) * lda]; | 
					
						
							|  |  |  |       if (j != 1) { | 
					
						
							|  |  |  |         t = -b[j - 1]; | 
					
						
							|  |  |  |         daxpy(j - 1, t, a + 0 + (j - 1)*lda, 1, b, 1); | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   /**
 | 
					
						
							|  |  |  |     Compute RSD or AB as required. | 
					
						
							|  |  |  |   */ | 
					
						
							|  |  |  |   if (cr || cab) { | 
					
						
							|  |  |  |     for (jj = 1; jj <= ju; jj++) { | 
					
						
							|  |  |  |       j = ju - jj + 1; | 
					
						
							|  |  |  |       if (qraux[j - 1] != 0.0) { | 
					
						
							|  |  |  |         temp = a[j - 1 + (j - 1) * lda]; | 
					
						
							|  |  |  |         a[j - 1 + (j - 1)*lda] = qraux[j - 1]; | 
					
						
							|  |  |  |         if (cr) { | 
					
						
							|  |  |  |           t = -ddot(n - j + 1, a + j - 1 + (j - 1) * lda, 1, rsd + j - 1, 1) | 
					
						
							|  |  |  |               / a[j - 1 + (j - 1) * lda]; | 
					
						
							|  |  |  |           daxpy(n - j + 1, t, a + j - 1 + (j - 1)*lda, 1, rsd + j - 1, 1); | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  |         if (cab) { | 
					
						
							|  |  |  |           t = -ddot(n - j + 1, a + j - 1 + (j - 1) * lda, 1, ab + j - 1, 1) | 
					
						
							|  |  |  |               / a[j - 1 + (j - 1) * lda]; | 
					
						
							|  |  |  |           daxpy(n - j + 1, t, a + j - 1 + (j - 1)*lda, 1, ab + j - 1, 1); | 
					
						
							|  |  |  |         } | 
					
						
							|  |  |  |         a[j - 1 + (j - 1)*lda] = temp; | 
					
						
							|  |  |  |       } | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   return info; | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | void dscal(int n, double sa, double x[], int incx) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DSCAL scales a vector by a constant. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     30 March 2007 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch, Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, 1979. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Charles Lawson, Richard Hanson, David Kincaid, Fred Krogh, | 
					
						
							|  |  |  |     Basic Linear Algebra Subprograms for Fortran Usage, | 
					
						
							|  |  |  |     Algorithm 539, | 
					
						
							|  |  |  |     ACM Transactions on Mathematical Software, | 
					
						
							|  |  |  |     Volume 5, Number 3, September 1979, pages 308-323. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of entries in the vector. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double SA, the multiplier. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, double X[*], the vector to be scaled. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCX, the increment between successive entries of X. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   int i; | 
					
						
							|  |  |  |   int ix; | 
					
						
							|  |  |  |   int m; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if (n <= 0) return; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if (incx == 1) { | 
					
						
							|  |  |  |     m = n % 5; | 
					
						
							|  |  |  |     for (i = 0; i < m; i++) | 
					
						
							|  |  |  |       x[i] = sa * x[i]; | 
					
						
							|  |  |  |     for (i = m; i < n; i = i + 5) { | 
					
						
							|  |  |  |       x[i]   = sa * x[i]; | 
					
						
							|  |  |  |       x[i + 1] = sa * x[i + 1]; | 
					
						
							|  |  |  |       x[i + 2] = sa * x[i + 2]; | 
					
						
							|  |  |  |       x[i + 3] = sa * x[i + 3]; | 
					
						
							|  |  |  |       x[i + 4] = sa * x[i + 4]; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   else { | 
					
						
							|  |  |  |     if (0 <= incx) | 
					
						
							|  |  |  |       ix = 0; | 
					
						
							|  |  |  |     else | 
					
						
							|  |  |  |       ix = (- n + 1) * incx; | 
					
						
							|  |  |  |     for (i = 0; i < n; i++) { | 
					
						
							|  |  |  |       x[ix] = sa * x[ix]; | 
					
						
							|  |  |  |       ix = ix + incx; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | void dswap(int n, double x[], int incx, double y[], int incy) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     DSWAP interchanges two vectors. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     30 March 2007 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     C version by John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Jack Dongarra, Cleve Moler, Jim Bunch, Pete Stewart, | 
					
						
							|  |  |  |     LINPACK User's Guide, | 
					
						
							|  |  |  |     SIAM, 1979. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Charles Lawson, Richard Hanson, David Kincaid, Fred Krogh, | 
					
						
							|  |  |  |     Basic Linear Algebra Subprograms for Fortran Usage, | 
					
						
							|  |  |  |     Algorithm 539, | 
					
						
							|  |  |  |     ACM Transactions on Mathematical Software, | 
					
						
							|  |  |  |     Volume 5, Number 3, September 1979, pages 308-323. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of entries in the vectors. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, double X[*], one of the vectors to swap. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCX, the increment between successive entries of X. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input/output, double Y[*], one of the vectors to swap. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int INCY, the increment between successive elements of Y. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   if (n <= 0) return; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   int i, ix, iy, m; | 
					
						
							|  |  |  |   double temp; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   if (incx == 1 && incy == 1) { | 
					
						
							|  |  |  |     m = n % 3; | 
					
						
							|  |  |  |     for (i = 0; i < m; i++) { | 
					
						
							|  |  |  |       temp = x[i]; | 
					
						
							|  |  |  |       x[i] = y[i]; | 
					
						
							|  |  |  |       y[i] = temp; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |     for (i = m; i < n; i = i + 3) { | 
					
						
							|  |  |  |       temp = x[i]; | 
					
						
							|  |  |  |       x[i] = y[i]; | 
					
						
							|  |  |  |       y[i] = temp; | 
					
						
							|  |  |  |       temp = x[i + 1]; | 
					
						
							|  |  |  |       x[i + 1] = y[i + 1]; | 
					
						
							|  |  |  |       y[i + 1] = temp; | 
					
						
							|  |  |  |       temp = x[i + 2]; | 
					
						
							|  |  |  |       x[i + 2] = y[i + 2]; | 
					
						
							|  |  |  |       y[i + 2] = temp; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  |   else { | 
					
						
							|  |  |  |     ix = (incx >= 0) ? 0 : (-n + 1) * incx; | 
					
						
							|  |  |  |     iy = (incy >= 0) ? 0 : (-n + 1) * incy; | 
					
						
							|  |  |  |     for (i = 0; i < n; i++) { | 
					
						
							|  |  |  |       temp = x[ix]; | 
					
						
							|  |  |  |       x[ix] = y[iy]; | 
					
						
							|  |  |  |       y[iy] = temp; | 
					
						
							|  |  |  |       ix = ix + incx; | 
					
						
							|  |  |  |       iy = iy + incy; | 
					
						
							|  |  |  |     } | 
					
						
							|  |  |  |   } | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | void qr_solve(double x[], int m, int n, double a[], double b[]) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | /**
 | 
					
						
							|  |  |  |   Purpose: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     QR_SOLVE solves a linear system in the least squares sense. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Discussion: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     If the matrix A has full column rank, then the solution X should be the | 
					
						
							|  |  |  |     unique vector that minimizes the Euclidean norm of the residual. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     If the matrix A does not have full column rank, then the solution is | 
					
						
							|  |  |  |     not unique; the vector X will minimize the residual norm, but so will | 
					
						
							|  |  |  |     various other vectors. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Licensing: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     This code is distributed under the GNU LGPL license. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Modified: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     11 September 2012 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Author: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     John Burkardt | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Reference: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     David Kahaner, Cleve Moler, Steven Nash, | 
					
						
							|  |  |  |     Numerical Methods and Software, | 
					
						
							|  |  |  |     Prentice Hall, 1989, | 
					
						
							|  |  |  |     ISBN: 0-13-627258-4, | 
					
						
							|  |  |  |     LC: TA345.K34. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   Parameters: | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int M, the number of rows of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, int N, the number of columns of A. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double A[M*N], the matrix. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Input, double B[M], the right hand side. | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |     Output, double QR_SOLVE[N], the least squares solution. | 
					
						
							|  |  |  | */ | 
					
						
							|  |  |  | { | 
					
						
							|  |  |  |   double a_qr[n * m], qraux[n], r[m], tol; | 
					
						
							|  |  |  |   int ind, itask, jpvt[n], kr, lda; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   r8mat_copy(a_qr, m, n, a); | 
					
						
							|  |  |  |   lda = m; | 
					
						
							|  |  |  |   tol = r8_epsilon() / r8mat_amax(m, n, a_qr); | 
					
						
							|  |  |  |   itask = 1; | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  |   ind = dqrls(a_qr, lda, m, n, tol, &kr, b, x, r, jpvt, qraux, itask); UNUSED(ind); | 
					
						
							|  |  |  | } | 
					
						
							|  |  |  | /******************************************************************************/ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | #endif
 |